我想傳回給定使用者的約會清單(約會表包含 user_id
和 post_id
)。
問題是,返回的集合只得到了第一次約會的名字和地點。
public function index() { // Retrieve all appointments from the user $appointments = Appointment::where('user_id', Auth::user()->id)->get(); // Retrieve all post IDs associated with the appointments $postIds = $appointments->pluck('post_id')->toArray(); // Retrieve all posts with the associated post IDs $posts = Post::whereIn('id', $postIds)->get()->keyBy('id'); // Assign post details to each appointment $appointments = $appointments->map(function ($appointment) use ($posts) { $postId = $appointment->post_id; if (isset($posts[$postId])) { $post = $posts[$postId]; $appointment->name = $post->name; $appointment->place = $post->place; } else { // For debugging purposes, log the missing post details Log::info("Post details not found for appointment: " . $appointment->id); } return $appointment; }); return $appointments; }
我在郵差中得到的結果如下:
[ { "id": 4, "user_id": 9, "post_id": 2, "date": "6/14/2023", "day": "Wednesday", "time": "12:00 PM", "status": "upcoming", "created_at": "2023-06-12T17:19:58.000000Z", "updated_at": "2023-06-12T17:19:58.000000Z", "name": "Biskra", "place": "Tolga" }, { "id": 5, "user_id": 9, "post_id": 9, "date": "6/24/2023", "day": "Saturday", "time": "14:00 PM", "status": "cancel", "created_at": "2023-06-12T18:53:45.000000Z", "updated_at": "2023-06-12T18:53:45.000000Z" }, { "id": 6, "user_id": 9, "post_id": 8, "date": "6/17/2023", "day": "Saturday", "time": "12:00 PM", "status": "complete", "created_at": "2023-06-13T01:43:14.000000Z", "updated_at": "2023-06-13T01:43:14.000000Z" } ]
我想取得使用者的約會清單以及每個約會的資訊(日期,時間,日期,post_name,post_place)
問題在於嘗試修改原始約會以獲得結果,請檢查您的程式碼
結果必須放置在不同的變數中才能得到正確的結果