如何從結果集中僅顯示最低值（MYSQL）

Question

我有以下聲明：

select DATE(recieved_on) as Day, round (count(*) / 24)  AS 'average'
from message
where facility in ('FACID')
AND received on BETWEEN '2022-05-29 00:00:00' AND '2022-06-04 23:59:59'
GROUP BY DATE(received on);

它提供了以下結果集：

日	平均
日期	值
日期	值
日期	值
日期	值
日期	值
日期	值
日期	值

如何只顯示結果集中的最低值而不是全部 7 個值？

Answer 1

您只需使用 order by 和 limit 即可：

select DATE(recieved_on) as Day, round (count(*) / 24) AS 'average'
from message
where facility in ('FACID') AND received on BETWEEN '2022-05-29 00:00:00' AND '2022-06-04 23:59:59'
GROUP BY DATE(received on)
order by average
limit 1