shell - python实现把多级目录多个JS文件中包含某字符的字符串提取出来并加上标示存入一个文本文件中。

Question

一个草图：

现实现在文件夹和子文件夹下查找目标字符串，
但不知如何提取包含目标字符的字符串，并写入到新文件中。

#!/usr/bin/env python
#-*- coding:utf-8 -*-
import os, sys
import fnmatch

listonly = False
skipexts = ['.js']
def visitfile(fname,searchkey):
    global fcount,vcount
    try:
        if not listonly:
            if os.path.splitext(fname)[1] in skipexts:
                if open(fname).read().find(searchkey) != -1:
                    print '%s has %s '%(fname,searchkey)
                    fcount+=1
    except: pass
    vcount +=1

def visitor(args,directoryName,filesInDirectory):
    for fname in filesInDirectory:
        # 返回文件所在路径和文件名
        fpath = os.path.join(directoryName,fname)
        if not os.path.isdir(fpath):

            visitfile(fpath,args)

def searcher(startdir,searchkey):
    global fcount,vcount
    fcount = vcount = 0
    os.path.walk(startdir,visitor,searchkey)

if __name__=='__main__':
    # root=raw_input("type root directory:")
    root = '/home/jiangbin/findJS'
    key=raw_input("type key:")
    searcher(root,key)
    print 'Found in %d files,visited %d'%(fcount,vcount)

run

type key:JSQ
/home/jiangbin/findJS/XXX.js has JSQ 
/home/jiangbin/findJS/JSQ.js has JSQ 
Found in 2 files,visited 19

Answer 1

你不是完成得差不多了....

https://gist.github.com/wusisu/e08ee53513c4410cf9ddd1ba5b0b80f5
我幫你完成了

----但實際上，用shell就ok了--------

find . -type f -name "*.js" | xargs grep work_to_be_searched

find . -type f -name "*.js" | xargs grep work_to_be_searched > out.txt

• 這裡 find 的 type f 表示只顯示檔案 name 就是以 .js 結尾

• 透過 xargs 傳遞

• 用 grep 來搜尋關鍵字

• 最後用 > 導出

Answer 2

如果你用的是 linux，那我建議你用 grep 就好了:

$ ls mydir
a.js  b.js  c.js

$ grep JSQ mydir/*.js
mydir/a.js:abcdefg JSQ abcdefg
mydir/a.js:JSQ abcdefg abcdefg
mydir/a.js:abcdefg abcdefg JSQ
mydir/c.js:abcdefg JSQ abcdefg
mydir/c.js:JSQ abcdefg abcdefg
mydir/c.js:abcdefg abcdefg JSQ

(上面的例子裡，第一行的顯示有點問題，應該是這樣:grep JSQ mydir/*.js)

你也可以導到文件裡:

$ grep JSQ mydir/* > results.txt

然後你再從 results.txt 去整理和統計數據。

如果你堅持想要使用 Python，我寫了一個應該是比較優化的程式碼，你可以參考一下:

import os
import glob

def search(root, key, ftype='', logname=None):
    ftype = '*.'+ftype if ftype else '*'
    logname = logname or os.devnull
    symbol = os.path.join(root, ftype)
    fnames = glob.glob(symbol)
    vc = len(fnames)
    fc = 0

    with open(logname, 'w') as writer:
        for fname in fnames:
            found = False
            with open(fname) as reader:
                for idx, line in enumerate(reader):
                    line = line.strip()
                    if key in line.split():
                        line = line.replace(key, '**'+key+'**')
                        found = True
                        print('{} -- {}: {}'.format(fname, idx, line), file=writer)
            if found:
                fc = fc + 1
                print('{} has {}'.format(fname, key))

    return vc, fc

search(root, key, ftype='', logname=None)

• 會在 root 這個 path 底下

• 尋找副檔名為 ftype 的文件(如果沒給則全部的文件都接受)

• 在裡面搜尋是否包含 key 這個關鍵字

• 如果有給 logname，則會輸出關鍵字前後用 '**' highlight 的 log 文件，內容是包含該關鍵字的每一行

其實可以這樣用(search.py):

if __name__=='__main__':
    root = 'mydir'
    key = input("type key: ")
    vc, fc = search(root, key, 'js', logname='results')
    print('Found in {} files, visited {}'.format(fc, vc))

運行:

$ python3 search.py
type key: JSQ
mydir/c.js has JSQ
mydir/a.js has JSQ
Found in 2 files, visited 3

logfile results:

mydir/c.js -- 0: abcdefg **JSQ** abcdefg
mydir/c.js -- 1: **JSQ** abcdefg abcdefg
mydir/c.js -- 2: abcdefg abcdefg **JSQ**
mydir/a.js -- 0: abcdefg **JSQ** abcdefg
mydir/a.js -- 1: **JSQ** abcdefg abcdefg
mydir/a.js -- 2: abcdefg abcdefg **JSQ**

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我回答過的問題: Python-QA