PHP开发企业网站教程之添加新闻资讯
点击添加按钮 跳转到addne.php 页面
我们来看下 addne.php 代码:
<!DOCTYPE html> <html> <head> <meta charset="utf-8"> <title>添加新闻资讯</title> <style type="text/css"> .ipt{width:180px;height:30px;border-radius:5px; outline:none;border:1px solid #eee;box-sizing:border-box;padding-left:15px;} .txt{width:250px;height:200px;} .sub{width:50px;height:20px;border:1px solid #eee;background:#eee;color:#ff7575;} </style> </head> <body> <form method="post" action="addnews.php"> 标题:<input type="text" name="title" class="ipt"> </br></br> 内容:<textarea cols="50" rows="5" name="content" class="txt"></textarea></br></br> <select name="type"> <option value="0">公司公告</option> <option value="1">公司新闻</option> </select> </br></br> <input type="submit" value="添加" class="sub"> </form> </body> </html>
看如上代码:表单提交addnews.php 页面
下面我们来看以下addnews.php页面的代码:
<?php //添加新闻资讯 require_once('conn.php'); $title=$_POST['title']; $content = $_POST['content']; $type = $_POST['type']; $newtime = time(); $sql = "insert into `news`(title,type,content,newtime) values('$title','$type','$content','$newtime')"; $res = mysql_query($sql); if($res){ echo "<script>alert('添加新闻成功');location.href='news.php';</script>"; }else{ echo "<script>alert('添加新闻失败');location.href='news.php';</script>"; } ?>
获取表单信息,然后添加到数据库 表中,然后对其进行判断,是否添加成功