小弟最近做专题碰上瓶颈,想把两个范本的IF 整合,却找不到方法
1.--------------------------------------------- ------------------------------------------------
<code>header("Content-Type: text/html; charset=utf-8"); include("connsql.php"); //含入連結資料庫檔案 $seldb = @mysql_select_db("orderdrink"); //連結資料庫 if (!$seldb) die("資料庫選擇失敗!"); $sql_query = "SELECT `orderid`,`phone`,`name` FROM `orders` WHERE `finish`=0 ORDER BY `orderid` DESC"; $result = mysql_query($sql_query); $numrow = mysql_num_rows($result); $row_result = array(); $i = 0; while($row_result[$i] = mysql_fetch_array($result, MYSQL_ASSOC)){ $i++; }</code>
2.--------------------------------------------- -----------------------------------------------
header("Content-Type: text/html; charset=utf-8");
include("connsql.php"); //含入連結資料庫檔案
$seldb = @mysql_select_db("orderdrink"); //連結資料庫
if (!$seldb) die("資料庫選擇失敗!");
if (isset($_GET["update"])) {
$order = $_GET["update"];
$sql_query = "UPDATE `orders` SET `finish`=1 WHERE `orderid`='" . $order . "'";
$result = mysql_query($sql_query);
header("Location: index.php");
}
$row_detail = array();
$order = $_GET["order"];
$sql_query = "SELECT * FROM `orders` WHERE `orderid`='" . $order . "'";
$result = mysql_query($sql_query);
$numorder = 0;
$numorder = mysql_num_rows($result);
if($numorder>0) {
$row_order = mysql_fetch_array($result, MYSQL_ASSOC);
$sql_query = "SELECT * FROM `productdetail` WHERE `orderid`='" . $order . "'";
$result = mysql_query($sql_query);
$numdetail = mysql_num_rows($result);
$i = 0;
while($row_detail[$i] = mysql_fetch_array($result, MYSQL_ASSOC)) {
$i++;
}
}
?>
想请问网友该怎么做?
回复内容:
小弟最近做专题碰上瓶颈,想把两个范本的IF 整合,却找不到方法
1.--------------------------------------------- ------------------------------------------------
<code>header("Content-Type: text/html; charset=utf-8");
include("connsql.php"); //含入連結資料庫檔案
$seldb = @mysql_select_db("orderdrink"); //連結資料庫
if (!$seldb) die("資料庫選擇失敗!");
$sql_query = "SELECT `orderid`,`phone`,`name` FROM `orders` WHERE `finish`=0 ORDER BY `orderid` DESC";
$result = mysql_query($sql_query);
$numrow = mysql_num_rows($result);
$row_result = array();
$i = 0;
while($row_result[$i] = mysql_fetch_array($result, MYSQL_ASSOC)){
$i++;
}</code>
登录后复制
?>
2.--------------------------------------------- -----------------------------------------------
header("Content-Type: text/html; charset=utf-8");
include("connsql.php"); //含入連結資料庫檔案
$seldb = @mysql_select_db("orderdrink"); //連結資料庫
if (!$seldb) die("資料庫選擇失敗!");
if (isset($_GET["update"])) {
$order = $_GET["update"];
$sql_query = "UPDATE `orders` SET `finish`=1 WHERE `orderid`='" . $order . "'";
$result = mysql_query($sql_query);
header("Location: index.php");
}
$row_detail = array();
$order = $_GET["order"];
$sql_query = "SELECT * FROM `orders` WHERE `orderid`='" . $order . "'";
$result = mysql_query($sql_query);
$numorder = 0;
$numorder = mysql_num_rows($result);
if($numorder>0) {
$row_order = mysql_fetch_array($result, MYSQL_ASSOC);
$sql_query = "SELECT * FROM `productdetail` WHERE `orderid`='" . $order . "'";
$result = mysql_query($sql_query);
$numdetail = mysql_num_rows($result);
$i = 0;
while($row_detail[$i] = mysql_fetch_array($result, MYSQL_ASSOC)) {
$i++;
}
}
?>
想请问网友该怎么做?
链式写法,因为面向对象特性,可以返回this
http://segmentfault.com/a/1190000003069921?utm_source=APP&utm_medium=iOS&utm_campaign=socialShare