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如何去掉数据库重复记录并且只保留一条记录

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发布: 2016-06-07 14:59:36
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在n条记录里,存在着些相同的记录,如何能用SQL语句,删除掉重复并保留一条呢? 方法如下: 1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断 select * from peoplewhere peopleId in (select peopleId from people group by peopleId hav

在n条记录里,存在着些相同的记录,如何能用SQL语句,删除掉重复并保留一条呢?

方法如下:


1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断


select * from people
where peopleId in (select  peopleId  from  people  group  by  peopleId  having  count(peopleId) > 1)
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2、删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录


delete from people 
where peopleId  in (select  peopleId  from people  group  by  peopleId   having  count(peopleId) > 1)
and rowid not in (select min(rowid) from  people  group by peopleId  having count(peopleId )>1)
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3、查找表中多余的重复记录(多个字段)
select * from vitae a
where (a.peopleId,a.seq) in  (select peopleId,seq from vitae group by peopleId,seq  having count(*) > 1)
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4、删除表中多余的重复记录(多个字段),只留有rowid最小的记录


delete from vitae a
where (a.peopleId,a.seq) in  (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
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5、查找表中多余的重复记录(多个字段),不包含rowid最小的记录


select * from vitae a
where (a.peopleId,a.seq) in  (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
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