今天在编译Java程序的时候出现以下错误： No enclosing instance of type Main is accessible. Must qualify the allocation with an enclosing instance of type Main (e.g. x.new A() where x is an instance of Main). 我原来编写的源代码是这样的： publ
今天在编译Java程序的时候出现以下错误：
No enclosing instance of type Main is accessible. Must qualify the allocation with an enclosing instance of type Main (e.g. x.new A() where x is an instance of Main).
我原来编写的源代码是这样的：
public class Main
{
class Dog //定义一个“狗类”
{
private String name;
private int weight;
public Dog(String name, int weight)
{
this.setName(name);
this.weight = weight;
}
public int getWeight()
{
return weight;
}
public void setWeight(int weight)
{this.weight = weight;}
public void setName(String name)
{this.name = name;}
public String getName()
{return name;}
}
public static void main(String[] args)
{
Dog d1 = new Dog("dog1",1);
}
}
出现这个错误的时候，我一直不太理解。
在借鉴别人的解释之后才恍然大悟。
在代码中，我的Dog类是定义在Main中的内部类。Dog内部类是动态的内部类，而我的main方法是static静态的。
就好比静态的方法不能调用动态的方法一样。
有两种解决办法：
第一种：
将内部类Dog定义成静态static的类。
第二种：
将内部类Dog在Main类外边定义。
修改后的代码：
第一种：
public class Main
{
public static class Dog
{
private String name;
private int weight;
public Dog(String name, int weight)
{
this.setName(name);
this.weight = weight;
}
public int getWeight()
{
return weight;
}
public void setWeight(int weight)
{this.weight = weight;}
public void setName(String name)
{this.name = name;}
public String getName()
{return name;}
}
public static void main(String[] args)
{
Dog d1 = new Dog("dog1",1);
}
}
第二种：
public class Main
{
public static void main(String[] args)
{
Dog d1 = new Dog("dog1",1);
}
}
class Dog
{
private String name;
private int weight;
public Dog(String name, int weight)
{
this.setName(name);
this.weight = weight;
}
public int getWeight()
{
return weight;
}
public void setWeight(int weight)
{this.weight = weight;}
public void setName(String name)
{this.name = name;}
public String getName()
{return name;}
}
