MySQL中整条记录复制并插入方法

MySQL中整条记录复制并插入方法 大致方法是先查出所需要复制到记录然后财插入，条件是两个表的记录结果数据类型都必须完全一样才行哦。

从 MSSQL 中导出一个文章表，需要插入到 PHPCMS 中的内容表 phpcms_content 去，需要做到文章可以发布到不同的栏目中去。也就是说，需要复制一条记录，并修改其 catid，再插入到表尾的位置上

代码如下	复制代码
INSERT INTO phpcms_content (SELECT ".$r[$i]['aid']." + 520, ".$r[$i]['cateid'].", news_catid, catid, typeid, areaid, title, style, thumb, keywords, keywords, posids, url, listorder, status, userid, username, inputtime, updatetime, searchid, islink, prefix FROM phpcms_content WHERE contentid = '".$r[$i-1]['aid']."')

大致为：insert into a SELECT id+1, ...(其它字段) FROM a ;

下面PHP具体程序：

代码如下

复制代码

$query  = "SELECT * FROM articleincategory ORDER BY ArticleID  "; $result = $connector -> query($query); $i = 0; while($myrow = $connector -> fetch_array($result)) {  $r[$i]['aid'] = $myrow["ArticleID"];  $r[$i]['cateid'] = $myrow["CategoryID"];  $i++; } for($i = 0; $i {  if($i > 0)  {   if( $r[$i]['aid'] == $r[$i-1]['aid'] )   {    echo '第 '. $i. ' 条数据 '. $r[$i]['aid'] .' 与前一条数据 '. $r[$i-1]['aid'] .' 重复'.' ';    $sql = " INSERT INTO phpcms_content (SELECT ".$r[$i]['aid']." + 520, ".$r[$i]['cateid'].", news_catid, catid, typeid, areaid, title, style, thumb, keywords, keywords, posids, url, listorder, status, userid, username, inputtime, updatetime, searchid, islink, prefix FROM phpcms_content WHERE contentid = '".$r[$i-1]['aid']."') ";    //$sql = " INSERT INTO phpcms_c_news (SELECT ".$r[$i]['aid']." + 520, template, titleintact, content, groupids_view, readpoint, author, copyfrom, paginationtype, maxcharperpage, sub_title FROM phpcms_c_news WHERE contentid = '".$r[$i-1]['aid']."')  ";    echo $sql.' ';    //$result = $connector -> query($sql);    //INSERT INTO test (SELECT id + 10, name, class, score FROM test WHERE id = '1');   }      else if( $r[$i]['aid'] != $r[$i-1]['aid'] )   {    $sql = " UPDATE phpcms_content SET origin_cateid = '".$r[$i]['cateid']."' WHERE contentid = '".$r[$i]['aid']."'  ";    echo $sql.' ';    //$result = $connector -> query($sql);   }     } }

如果不需要插入，则更简单：insert into mytable (select * from mytable where id=1) ON DUPLICATE KEY UPDATE id=2;