ajax php的问题
有好几个checkbox循环出来,还有个文本框
<!--Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--><input name="ckID[]" type="checkbox" id="<?='ckID'.$row['MIS_id']?>" value="<?=$row['MIS_id']?>" onclick="showInfor(this.value)" /><div id="txtHint"><input name="txtid" type="text" id="txtid" /></div>
<!--Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/-->function showInfor(str) { //document.getElementById("txtid").value=str; //var str = document.geElementById("ckID").value; //document.write(str); var xmlhttp; if (id.length==0) { document.getElementById("txtid").value=""; return; } if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } else {// code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { //document.getElementById("show").innerHTML=xmlhttp.responseText; document.getElementById("txtid").value=xmlhttp.responseText; } } xmlhttp.open("GET","showSettle.php?q="+str,true); xmlhttp.send();}
<!--Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/-->$db = mysql_connect("localhost","root","1234");mysql_select_db("it database",$db);$q=$_GET['q']; // connecting to database and stuff... echo $q; $temp = mysql_query("SELECT MIS_id FROM materialinstorage WHERE MIS_id = '$q' "); echo $temp;$row = mysql_fetch_array($temp); $id =$row['MIS_id']; echo $id;
document.getElementById("txtid").value="";应该是这句,这是什么错啊 //跟你这句没关系的,这句只是设置文本框中的值为空if (id.length==0){ //是这段的处理,主要是id.length这个没有定义,不懂这段做什么,是判断复选框是否被选? 检查下这段 document.getElementById("txtid").value=""; return; }<div class="clear"></div>