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InnoDB中可以强制外键验证吗?

Susan Sarandon
发布: 2024-11-09 11:38:02
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Can Foreign Key Verification be Enforced in InnoDB?

InnoDB 中可以强制执行外键验证吗?

在具有外键约束的 InnoDB 表中维护数据完整性可能具有挑战性。在数据更新期间关闭外键检查可能会损害参照完整性,因此在更新完成后重新检查约束至关重要。

不幸的是,MySQL 没有提供直接机制来强制 InnoDB 重新检查特定表或的外键约束。一个数据库。但是,可以使用以下存储过程作为解决方法:

DELIMITER $$

DROP PROCEDURE IF EXISTS ANALYZE_INVALID_FOREIGN_KEYS$$

CREATE
    PROCEDURE `ANALYZE_INVALID_FOREIGN_KEYS`(
        checked_database_name VARCHAR(64), 
        checked_table_name VARCHAR(64), 
        temporary_result_table ENUM('Y', 'N'))

    LANGUAGE SQL
    NOT DETERMINISTIC
    READS SQL DATA

    BEGIN
        DECLARE TABLE_SCHEMA_VAR VARCHAR(64);
        DECLARE TABLE_NAME_VAR VARCHAR(64);
        DECLARE COLUMN_NAME_VAR VARCHAR(64); 
        DECLARE CONSTRAINT_NAME_VAR VARCHAR(64);
        DECLARE REFERENCED_TABLE_SCHEMA_VAR VARCHAR(64);
        DECLARE REFERENCED_TABLE_NAME_VAR VARCHAR(64);
        DECLARE REFERENCED_COLUMN_NAME_VAR VARCHAR(64);
        DECLARE KEYS_SQL_VAR VARCHAR(1024);

        DECLARE done INT DEFAULT 0;

        DECLARE foreign_key_cursor CURSOR FOR
            SELECT
                `TABLE_SCHEMA`,
                `TABLE_NAME`,
                `COLUMN_NAME`,
                `CONSTRAINT_NAME`,
                `REFERENCED_TABLE_SCHEMA`,
                `REFERENCED_TABLE_NAME`,
                `REFERENCED_COLUMN_NAME`
            FROM 
                information_schema.KEY_COLUMN_USAGE 
            WHERE 
                `CONSTRAINT_SCHEMA` LIKE checked_database_name AND
                `TABLE_NAME` LIKE checked_table_name AND
                `REFERENCED_TABLE_SCHEMA` IS NOT NULL;

        DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = 1;

        IF temporary_result_table = 'N' THEN
            DROP TEMPORARY TABLE IF EXISTS INVALID_FOREIGN_KEYS;
            DROP TABLE IF EXISTS INVALID_FOREIGN_KEYS;

            CREATE TABLE INVALID_FOREIGN_KEYS(
                `TABLE_SCHEMA` VARCHAR(64), 
                `TABLE_NAME` VARCHAR(64), 
                `COLUMN_NAME` VARCHAR(64), 
                `CONSTRAINT_NAME` VARCHAR(64),
                `REFERENCED_TABLE_SCHEMA` VARCHAR(64),
                `REFERENCED_TABLE_NAME` VARCHAR(64),
                `REFERENCED_COLUMN_NAME` VARCHAR(64),
                `INVALID_KEY_COUNT` INT,
                `INVALID_KEY_SQL` VARCHAR(1024)
            );
        ELSEIF temporary_result_table = 'Y' THEN
            DROP TEMPORARY TABLE IF EXISTS INVALID_FOREIGN_KEYS;
            DROP TABLE IF EXISTS INVALID_FOREIGN_KEYS;

            CREATE TEMPORARY TABLE INVALID_FOREIGN_KEYS(
                `TABLE_SCHEMA` VARCHAR(64), 
                `TABLE_NAME` VARCHAR(64), 
                `COLUMN_NAME` VARCHAR(64), 
                `CONSTRAINT_NAME` VARCHAR(64),
                `REFERENCED_TABLE_SCHEMA` VARCHAR(64),
                `REFERENCED_TABLE_NAME` VARCHAR(64),
                `REFERENCED_COLUMN_NAME` VARCHAR(64),
                `INVALID_KEY_COUNT` INT,
                `INVALID_KEY_SQL` VARCHAR(1024)
            );
        END IF;


        OPEN foreign_key_cursor;
        foreign_key_cursor_loop: LOOP
            FETCH foreign_key_cursor INTO 
            TABLE_SCHEMA_VAR, 
            TABLE_NAME_VAR, 
            COLUMN_NAME_VAR, 
            CONSTRAINT_NAME_VAR, 
            REFERENCED_TABLE_SCHEMA_VAR, 
            REFERENCED_TABLE_NAME_VAR, 
            REFERENCED_COLUMN_NAME_VAR;
            IF done THEN
                LEAVE foreign_key_cursor_loop;
            END IF;


            SET @from_part = CONCAT('FROM ', '`', TABLE_SCHEMA_VAR, '`.`', TABLE_NAME_VAR, '`', ' AS REFERRING ', 
                 'LEFT JOIN `', REFERENCED_TABLE_SCHEMA_VAR, '`.`', REFERENCED_TABLE_NAME_VAR, '`', ' AS REFERRED ', 
                 'ON (REFERRING', '.`', COLUMN_NAME_VAR, '`', ' = ', 'REFERRED', '.`', REFERENCED_COLUMN_NAME_VAR, '`', ') ', 
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