使用 GroupBy 方法对数组中的对象进行分组
Python 强大的 groupby 方法可以根据选定的属性对对象进行高效分组。如果您需要执行此类分组操作,groupby 提供了一个方便的解决方案。
例如,考虑以下对象数组:
[ { Phase: "Phase 1", Step: "Step 1", Task: "Task 1", Value: "5" }, { Phase: "Phase 1", Step: "Step 1", Task: "Task 2", Value: "10" }, { Phase: "Phase 1", Step: "Step 2", Task: "Task 1", Value: "15" }, { Phase: "Phase 1", Step: "Step 2", Task: "Task 2", Value: "20" }, { Phase: "Phase 2", Step: "Step 1", Task: "Task 1", Value: "25" }, { Phase: "Phase 2", Step: "Step 1", Task: "Task 2", Value: "30" }, { Phase: "Phase 2", Step: "Step 2", Task: "Task 1", Value: "35" }, { Phase: "Phase 2", Step: "Step 2", Task: "Task 2", Value: "40" } ]
按 Phase 对对象进行分组并计算总和值,我们使用:
from itertools import groupby def sum_value(objects): return sum(int(obj["Value"]) for obj in objects) objects.sort(key=lambda obj: obj["Phase"]) grouped_by_phase = groupby(objects, key=lambda obj: obj["Phase"]) result = [{ "Phase": phase, "Value": sum_value(objects) } for phase, objects in grouped_by_phase] print(result)
这会产生所需的输出:
[{"Phase": "Phase 1", "Value": 50}, {"Phase": "Phase 2", "Value": 130}]
或者,要按阶段和步骤进行分组,我们可以使用多个级别的分组:
grouped_by_phase_and_step = groupby(objects, key=lambda obj: (obj["Phase"], obj["Step"])) result = [{ "Phase": phase, "Step": step, "Value": sum_value(objects) } for (phase, step), objects in grouped_by_phase_and_step] print(result)
这将返回:
[{"Phase": "Phase 1", "Step": "Step 1", "Value": 15}, {"Phase": "Phase 1", "Step": "Step 2", "Value": 35}, {"Phase": "Phase 2", "Step": "Step 1", "Value": 55}, {"Phase": "Phase 2", "Step": "Step 2", "Value": 75}]
通过Python多功能的groupby方法,您可以轻松高效地对对象数组中的数据进行分组和聚合,满足您的各种分组需求。
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