问题:
COLUMNS_UPDATED 方法是已知的,但是需要更快的技术来捕获 XML 格式的修改字段值以进行复制
自动例行查询:
CREATE TRIGGER DBCustomers_Insert ON DBCustomers AFTER UPDATE AS BEGIN DECLARE @sql as NVARCHAR(1024); SET @sql = 'SELECT '; -- HELP NEEDED FOR FOLLOWING LINE... -- I can manually write every column, but need an automated way that works with any column specifications for each column, if its modified append $sql = ',' + columnname... SET @sql = $sql + ' FROM inserted FOR XML RAW'; DECLARE @x as XML; SET @x = CAST(EXEC(@sql) AS XML); .. use @x END
替代解决方案:
此响应呈现而不是使用 COLUMNS_UPDATED解决该问题的替代方法。它涉及对插入的表和删除的表进行逆透视以创建键、字段值和字段名称列。通过连接和过滤这两个未透视表,仅识别修改、删除和插入的行。
示例:
-- Setup tables and data CREATE TABLE dbo.Sample_Table (ContactID int, Forename varchar(100), Surname varchar(100), Extn varchar(16), Email varchar(100), Age int ); INSERT INTO Sample_Table VALUES (1,'Bob','Smith','2295','[email protected]',24); ... -- Create trigger CREATE TRIGGER TriggerName ON dbo.Sample_Table FOR DELETE, INSERT, UPDATE AS BEGIN -- Unpivot deleted and inserted tables WITH deleted_unpvt AS ( SELECT ContactID, FieldName, FieldValue FROM (SELECT ContactID, Forename, Surname, Extn, Email, Age FROM deleted) p UNPIVOT (FieldValue FOR FieldName IN (Forename, Surname, Extn, Email, Age)) AS deleted_unpvt ), inserted_unpvt AS ( SELECT ContactID, FieldName, FieldValue FROM (SELECT ContactID, Forename, Surname, Extn, Email, Age FROM inserted) p UNPIVOT (FieldValue FOR FieldName IN (Forename, Surname, Extn, Email, Age)) AS inserted_unpvt ) -- Join tables and capture changes INSERT INTO Sample_Table_Changes (ContactID, FieldName, FieldValueWas, FieldValueIs) SELECT Coalesce (D.ContactID, I.ContactID) ContactID , Coalesce (D.FieldName, I.FieldName) FieldName , D.FieldValue as FieldValueWas , I.FieldValue AS FieldValueIs FROM deleted_unpvt d FULL OUTER JOIN inserted_unpvt i on D.ContactID = I.ContactID AND D.FieldName = I.FieldName WHERE D.FieldValue <> I.FieldValue -- Changes OR (D.FieldValue IS NOT NULL AND I.FieldValue IS NULL) -- Deletions OR (D.FieldValue IS NULL AND I.FieldValue IS NOT NULL) -- Insertions END -- Execute changes UPDATE Sample_Table SET age = age+1; ... -- Output results SELECT *, SQL_VARIANT_PROPERTY(FieldValueWas, 'BaseType') FieldBaseType, SQL_VARIANT_PROPERTY(FieldValueWas, 'MaxLength') FieldMaxLength from Sample_Table_Changes;
替代解决方案:
以上是如何使用 XML 或替代方法有效捕获 SQL Server UPDATE 触发器中的修改字段?的详细内容。更多信息请关注PHP中文网其他相关文章!