Day-Dictionary，使用嵌套循环的字符频率

字典-{}

字典用于以键：值对的形式存储数据值。
字典是一个有序的、可更改的、不允许重复的集合。
在字典中，每个元素都可以通过它们的键来访问，而不是通过索引。
如果字典不包含该键，则输出将为“KeyError”。

示例：

thisdict = {
  "brand": "Ford",
  "model": "Mustang",
  "year": 1964
}

student = {"name":"raja", "class":5}

print(thisdict)
print(student)

{'brand': 'Ford', 'model': 'Mustang', 'year': 1964}
{'name': 'raja', 'class': 5}

1。查找字符串中每个字母的频率

s = 'lakshmipritha'
name = list(s)
j = 0 
while j<len(name):
    key = name[j]
    count = 1
    i = j+1
    if key != '*':
        while i<len(name):
            if key == name[i]:
                name[i] = '*'
                count+=1
            i+=1
        print(key, count)
    j+=1

l 1
a 2
k 1
s 1
h 2
m 1
i 2
p 1
r 1
t 1

2。字母只出现一次

s = 'lakshmipritha'
name = list(s)
j = 0 
while j<len(name):
    key = name[j]
    count = 1
    i = j+1
    if key != '*':
        while i<len(name):
            if key == name[i]:
                name[i] = '*'
                count+=1
            i+=1
    if count == 1 and key!='*':
        print(key, count)
    j+=1

l 1
k 1
s 1
m 1
p 1
r 1
t 1

3。最常见的字母

s = 'lakshmipritha'
name = list(s)
j = 0 
while j<len(name):
    key = name[j]
    count = 1
    i = j+1
    if key != '*':
        while i<len(name):
            if key == name[i]:
                name[i] = '*'
                count+=1
            i+=1
    if count != 1 and key!='*':
        print(key, count)
    j+=1

a 2
h 2
i 2

4。第一个不重复的字母

s = 'lakshmipritha'
name = list(s)
j = 0 
while j<len(name):
    key = name[j]
    count = 1
    i = j+1
    if key != '*':
        while i<len(name):
            if key == name[i]:
                name[i] = '*'
                count+=1
            i+=1
    if count == 1 and key!='*':
        print(key, count)
        break
    j+=1

l 1

5。第一个重复的字母

s = 'lakshmipritha'
name = list(s)
j = 0 
while j<len(name):
    key = name[j]
    count = 1
    i = j+1
    if key != '*':
        while i<len(name):
            if key == name[i]:
                name[i] = '*'
                count+=1
            i+=1
    if count != 1 and key!='*':
        print(key, count)
        break
    j+=1

a 2

6。最后一个不重复的字母

last = ' '
last_count = 0 
s = 'lakshmipritha'
name = list(s)
j = 0 
while j<len(name):
    key = name[j]
    count = 1
    i = j+1
    if key != '*':
        while i<len(name):
            if key == name[i]:
                name[i] = '*'
                count+=1
            i+=1
    if count == 1 and key!='*':
            last = key
            last_count = count
        #print(key, count)
    j+=1

print(last, last_count)

t 1

7。最后重复的字母

last = ' '
last_count = 0 
s = 'lakshmipritha'
name = list(s)
j = 0 
while j<len(name):
    key = name[j]
    count = 1
    i = j+1
    if key != '*':
        while i<len(name):
            if key == name[i]:
                name[i] = '*'
                count+=1
            i+=1
    if count != 1 and key!='*':
            last = key
            last_count = count
        #print(key, count)
    j+=1

print(last, last_count)

i 2

8。最常见的字母

s = 'lakshmipritha'
name = list(s)
j = 0 
last = ' '
last_count = 0 

while j<len(name):
    key = name[j]
    count = 1
    i = j+1
    if key != '*':
        while i<len(name):
            if key == name[i]:
                name[i] = '*'
                count+=1
            i+=1
    if count != 1 and key!='*':
        if count>last_count:
            last = key
            last_count = count
    j+=1

print(last, last_count)

a 2

9。元音出现频率 (a,e,i,o,u)

vowels = ['a','e','i','o','u']
last = ' '
last_count = 0 
s = 'lakshmipritha'
name = list(s)
j = 0 
while j<len(name):
    key = name[j]
    if key in vowels:
        count = 1
        i = j+1
        if key != '*':
            while i<len(name):
                if key == name[i]:
                    name[i] = '*'
                    count+=1
                i+=1
        if key!='*':
            print(key, count)
    j+=1

a 2
i 2

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