ajax接受不到返回的信息
a.html:
<br />
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><br />
<html xmlns="http://www.w3.org/1999/xhtml"><br />
<head><br />
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" /><br />
<title>无标题文档</title><br />
<script language='javascript' type='text/javascript' src="js/ajax.js"></script><br />
<script language='javascript' type='text/javascript' src="js/jquery.js"></script><br />
<script type="text/javascript"><br />
function check()<br />
{<br />
var con = document.getElementById('con').value;<br />
//alert(con);<br />
<br />
//创建ajax<br />
var ajax = createAjax();<br />
//是否创建成功<br />
//alert (ajax);<br />
var data = new Date();<br />
<br />
var urlStr = 'b.php?action='+data.getTime();<br />
//alert(urlStr);<br />
$.ajax({<br />
url:urlStr,<br />
datatype: "json", <br />
cache: false,<br />
success:function(response){<br />
alert(response);<br />
}<br />
}); <br />
}<br />
</script><br />
</head><br />
<br />
<body><br />
<form action='' method='post' enctype="application/x-www-form-urlencoded"><br />
<input type='text' name='con' id='con' value='' /><br />
<input type='submit' name='sub' value='提交' onclick='check()'/><br />
</form><br />
</body><br />
</html><br />
<br /> echo true;<br />
