真诚自定义，多谢

真诚求一个自定义，谢谢

本帖最后由 bonlog 于 2012-12-07 09:08:21 编辑

当输入
Monday/Tuesday/Wednesday/Thursday/Friday/Saturday/Sunday
输出
1,2,3,4,5,6,7

为了便于扩展，最好使用数组。

------解决方案--------------------

function foo($s) {<br />
  $dict = array_flip(explode(',', '/,monday,tuesday,wednesday,thursday,friday,saturday,sunday'));<br />
  $dict['/'] = ',';<br />
  return strtr(strtolower($s), $dict);<br />
}<br />
<br />
echo foo('Monday/Tuesday/Wednesday/Thursday/Friday/Saturday/Sunday');<br />

1,2,3,4,5,6,7

------解决方案--------------------
空格和'/'均作处理

<br />
function foo($s) {<br />
	$array=array('monday'=>1,<br />
							'tuesday'=>2,<br />
							'wednesday'=>3,<br />
							'thursday'=>4,<br />
							'friday'=>5,<br />
							'saturday'=>6,<br />
							'sunday'=>7,<br />
							'/'=>',',' '=>',');<br />
  return strtr(strtolower($s), $array);<br />
} <br />
echo foo('Monday Tuesday Wednesday/Thursday/Friday/Saturday/Sunday');<br />

------解决方案--------------------

<br>
function foo($s) {<br>
    $array= array('monday'   =&gt; 1,<br>
                 'tuesday'  =&gt; 2,<br>
                 'wednesday'=&gt; 3,<br>
                 'thursday' =&gt; 4,<br>
                 'friday'   =&gt; 5,<br>
                 'saturday' =&gt; 6,<br>
                 'sunday'   =&gt; 7,<br>
                );<br>
<br>
    $sa = preg_split('/\W/',strtolower($s));<br>
    $arr = array();<br>
    foreach ($sa as $v) {<br>
        if(is_numeric($v)) {<br>
            $t = array_values($array);<br>
            $arr[] = $t[$v-1];<br>
        }<br>
        else if (isset($array[$v])) {<br>
            $arr[] = $array[$v];<br>
        }<br>
        else {<br>
            foreach ($array as $k1 =&gt; $v1 )  {<br>
                if ( substr($k1, 0, 4) == $v ) {<br>
                    $arr[] = $v1; break;<br>
                } <div class="clear">
                 
              
              
        
            </div>