求在一组数据内至多包含2个数据的记录个数，谢谢

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发布： 2016-06-13 13:29:46

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求在一组数据内至多包含2个数据的记录个数，多谢
原数据库table存储类似于下面的信息有好多记录
通过select l1,l2,l3,l4,l5 from table 可以得到如下数据

1 2 3 4 5
1 3 8 14 16
16 18 22 24 26
15 14 23 28 30
26 28 30 31 33

现在希望从这5条记录中按如下限定输出，即$arr=array（1,8,14,20,22,24,26,29，30,31,32,33），求在$arr中至多出现2个数字的记录是什么，当然可以选择从上面得出的记录中选，如果能在select的where条件中限定就更好了。先行谢过啦！~~~

------解决方案--------------------
中间的from之后一串union all替换为你的table

SQL code


SELECT * FROM(SELECT *,(if(find_in_set(a, '1,8,14,20,22,24,26,29,30,31,32,33'), 1, 0)  + if(find_in_set(b, '1,8,14,20,22,24,26,29,30,31,32,33'), 1, 0) + if(find_in_set(c, '1,8,14,20,22,24,26,29,30,31,32,33'), 1, 0) + if(find_in_set(d, '1,8,14,20,22,24,26,29,30,31,32,33'), 1, 0) + if(find_in_set(e, '1,8,14,20,22,24,26,29,30,31,32,33'), 1, 0) ) cnt FROM (SELECT 1 a, 2 b, 3 c, 4 d, 5 e union all
SELECT 1, 3, 8, 14, 16 union all
SELECT 16, 18, 22, 24, 26 union all
SELECT 15, 14, 23, 28, 30 union all
SELECT 26, 28, 30, 31, 33) t) s WHERE cnt<font color="#e78608">------解决方案--------------------</font><br>

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PHP code

mysql_connect();
mysql_select_db('test');
mysql_query('DROP TABLE IF EXISTS tset');
mysql_query('
CREATE TABLE IF NOT EXISTS test (
  id int(11) NOT NULL AUTO_INCREMENT,
  l1 varchar(2) NULL,
  l2 varchar(2) NULL,
  l3 varchar(2) NULL,
  l4 varchar(2) NULL,
  l5 varchar(2) NULL,
  PRIMARY KEY (`id`)
) ENGINE=MyISAM
');
mysql_query('TRUNCATE TABLE test');
mysql_query("insert into test (l1, l2, l3, l4, l5) values
('1', '2', '3', '4', '5'),
('1', '3', '8', '14', '16'),
('16', '18', '22', '24', '26'),
('15', '16', ' 23', '28', '3'),
('26', '28', '30', '31', '33')
");

$arr = array(1,8,14,20,21,24,26,29,30,31,32,33);
$s = "select '" .join("' as ch union all select '", $arr) . "'";

$sql = "select count(*) as cnt, a.* from 
  (select id, concat(l1,',',l2,',',l3,',',l4,',',l5) as p from test) a
  left join 
  ($s) b
  on find_in_set(b.ch, a.p) group by a.id HAVING cnt

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