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preg_replace怎么将src="/n1/images替换成src="images

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Jun 23, 2016 pm 01:31 PM

preg_replace怎么将src="/n1/images替换成src="images
src="/n1/images 中的n1 可能是其他字符，比如说m2或者py等。
不懂正则替换，请指点。

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$s =<<< TXT<img  src="/static/imghw/default1.png"  data-src="/n1/images"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" ><img  src="/static/imghw/default1.png"  data-src="/x2/images1"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" ><img  src="/static/imghw/default1.png"  data-src="/a/b/images2"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" >TXT;echo preg_replace('#(?<=src=").*/([^"]+)#', '$1', $s);

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<img  src="/static/imghw/default1.png"  data-src="images"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" ><img  src="/static/imghw/default1.png"  data-src="images1"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" ><img  src="/static/imghw/default1.png"  data-src="images2"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" >

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$s =<<< TXT<img  src="/static/imghw/default1.png"  data-src="/n1/images"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" ><img  src="/static/imghw/default1.png"  data-src="/x2/images1"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" ><img  src="/static/imghw/default1.png"  data-src="/a/b/images2"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" >TXT;echo preg_replace('#(?<=src=").*/([^"]+)#', '$1', $s);

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<img  src="/static/imghw/default1.png"  data-src="images"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" ><img  src="/static/imghw/default1.png"  data-src="images1"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" ><img  src="/static/imghw/default1.png"  data-src="images2"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" >

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谢谢版主，但如果是

怎么办？

preg_replace怎么将src= 替换成类似的应该怎么做，

你的需求不明确，前后矛盾，到底保留文件本身，还是保留文件名以及他的父级目录。

其实就是将

替换成

意思是将 images前面的目录删除

$str="src='/n1sss/images'“;

$zz="/src='\/.*\/(.*?)'/";

echo preg_replace($zz,'$1',$str);

这个 $zz="/src='\/.*\/(.*?)'/"; 在PHP里面就有错误

<?php$s =<<< TXT<img  src="/static/imghw/default1.png"  data-src="/a/b/images/hehehahha"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" >TXT;$pattern="/\/.*\/(.*?)\/(.*?)/";echo preg_replace($pattern, '$1/$2', $s);?>

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<?php$s =<<< TXT<img  src="/static/imghw/default1.png"  data-src="/a/b/images/hehehahha"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" >TXT;$pattern="/\/.*\/(.*?)\/(.*?)/";echo preg_replace($pattern, '$1/$2', $s);?>

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谢谢版主的回答，可能我的问题说的不是很明确，
利用preg_replace怎么将images前面的目录删除掉
将

或者

<?php$s =<<< TXT<img  src="/static/imghw/default1.png"  data-src="/a/b/images/hehehahha"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" >TXT;$pattern="/\/.*\/(.*?)\/(.*?)/";echo preg_replace($pattern, '$1/$2', $s);?>

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还请再帮帮忙

$s =<<< TXT<img  src="/static/imghw/default1.png"  data-src="/n1/images"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" ><img  src="/static/imghw/default1.png"  data-src="/x2/images1"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" ><img  src="/static/imghw/default1.png"  data-src="/a/b/images2"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" ><img  src="/static/imghw/default1.png"  data-src="/a/b/images2/hehehahha"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" >TXT;$n = 0; //只留文件名echo preg_replace("#(?<=src=['\"]).*/((?:.*/){{$n}}[^'\"]+)#", '$1', $s);$n = 1; //保留一级目录echo preg_replace("#(?<=src=['\"]).*/((?:.*/){{$n}}[^'\"]+)#", '$1', $s);$n = 2; //保留二级目录echo preg_replace("#(?<=src=['\"]).*/((?:.*/){{$n}}[^'\"]+)#", '$1', $s);

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<img  src="/static/imghw/default1.png"  data-src="images"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" ><img  src="/static/imghw/default1.png"  data-src="images1"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" ><img  src="/static/imghw/default1.png"  data-src="images2"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" >

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$s =<<< TXT<img  src="/static/imghw/default1.png"  data-src="/n1/images"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" ><img  src="/static/imghw/default1.png"  data-src="/x2/images1"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" ><img  src="/static/imghw/default1.png"  data-src="/a/b/images2"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" ><img  src="/static/imghw/default1.png"  data-src="/a/b/images2/hehehahha"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" >TXT;$n = 0; //只留文件名echo preg_replace("#(?<=src=['\"]).*/((?:.*/){{$n}}[^'\"]+)#", '$1', $s);$n = 1; //保留一级目录echo preg_replace("#(?<=src=['\"]).*/((?:.*/){{$n}}[^'\"]+)#", '$1', $s);$n = 2; //保留二级目录echo preg_replace("#(?<=src=['\"]).*/((?:.*/){{$n}}[^'\"]+)#", '$1', $s);

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<img  src="/static/imghw/default1.png"  data-src="images"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" ><img  src="/static/imghw/default1.png"  data-src="images1"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" ><img  src="/static/imghw/default1.png"  data-src="images2"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" >

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$s =<<< TXT<img  src="/static/imghw/default1.png"  data-src="/n1/images"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" ><img  src="/static/imghw/default1.png"  data-src="/x2/images1"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" ><img  src="/static/imghw/default1.png"  data-src="/a/b/images2"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" ><img  src="/static/imghw/default1.png"  data-src="/a/b/images2/hehehahha"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" >TXT;$n = 0; //只留文件名echo preg_replace("#(?<=src=['\"]).*/((?:.*/){{$n}}[^'\"]+)#", '$1', $s);$n = 1; //保留一级目录echo preg_replace("#(?<=src=['\"]).*/((?:.*/){{$n}}[^'\"]+)#", '$1', $s);$n = 2; //保留二级目录echo preg_replace("#(?<=src=['\"]).*/((?:.*/){{$n}}[^'\"]+)#", '$1', $s);

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<img  src="/static/imghw/default1.png"  data-src="images"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" ><img  src="/static/imghw/default1.png"  data-src="images1"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" ><img  src="/static/imghw/default1.png"  data-src="images2"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" >

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$s =<<< TXT<img  src="/static/imghw/default1.png"  data-src="/n1/images"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" ><img  src="/static/imghw/default1.png"  data-src="/x2/images1"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" ><img  src="/static/imghw/default1.png"  data-src="/a/b/images2"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" ><img  src="/static/imghw/default1.png"  data-src="/a/b/images2/hehehahha"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" >TXT;$n = 0; //只留文件名echo preg_replace("#(?<=src=['\"]).*/((?:.*/){{$n}}[^'\"]+)#", '$1', $s);$n = 1; //保留一级目录echo preg_replace("#(?<=src=['\"]).*/((?:.*/){{$n}}[^'\"]+)#", '$1', $s);$n = 2; //保留二级目录echo preg_replace("#(?<=src=['\"]).*/((?:.*/){{$n}}[^'\"]+)#", '$1', $s);

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<img  src="/static/imghw/default1.png"  data-src="images"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" ><img  src="/static/imghw/default1.png"  data-src="images1"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" ><img  src="/static/imghw/default1.png"  data-src="images2"  class="lazy"   alt="preg_replace怎么将src="/n1/images替换成src="images" >

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谢谢版主的回答，我有一个文件夹images，我就想保留images文件夹以及后面的目录，images后面的目录有几级是未知的。还请版主帮个忙

$str="src='/n1sss/images'“;

$zz="/src='\/.*\/(.*?)'/";

echo preg_replace($zz,'$1',$str);

我都运行过的没问题，才发出来的啊

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