求数组重组代码

数组 重组

我现在有一个数组如下:
[0] => Array
    (
        [size] => 123
        [path] => Array
            (
                [0] => a
                [1] => b
                [2] => c
                [3] => abc
            )

    )

[1] => Array
    (
        [size] => 456
        [path] => Array
            (
                [0] => d
                [1] => e
                [2] => f
                [3] => def
            )
    )
    
想重组成如下数组样式,请问怎么写代码啊?

[0] => Array
    (
        [a] => Array(
            [b] => Array(
                [c] => Array(
                    [size] => '123',
                    [name] => 'abc'
                )
            )
        )
    )

[1] => Array
    (
        [d] => Array(
            [e] => Array(
                [f] => Array(
                    [size] => '456',
                    [name] => 'def'
                )
            )
        )
    )

回复讨论(解决方案)

$arr=array(    '0' => Array    (        'size' => 123,        'path' => Array            (                '0' => 'a',                '1' => 'b',                '2' => 'c',                '3' => 'abc',            )    ),    '1' => Array    (        'size' => 456,        'path' => Array            (                '0' => 'd',                '1' => 'e',                '2' => 'f',                '3' => 'def',            )    ));$ar=array();foreach($arr as $k=>$v){     $ar[$k][$v['path'][0]][$v['path'][1]][$v['path'][2]]['size']=$v['size'];	 $ar[$k][$v['path'][0]][$v['path'][1]][$v['path'][2]]['name']=$v['path'][3];}print_r($ar);

$arr=array(    '0' => Array    (        'size' => 123,        'path' => Array            (                '0' => 'a',                '1' => 'b',                '2' => 'c',                '3' => 'abc',            )    ),    '1' => Array    (        'size' => 456,        'path' => Array            (                '0' => 'd',                '1' => 'e',                '2' => 'f',                '3' => 'def',            )    ));$ar=array();foreach($arr as $k=>$v){     $ar[$k][$v['path'][0]][$v['path'][1]][$v['path'][2]]['size']=$v['size'];	 $ar[$k][$v['path'][0]][$v['path'][1]][$v['path'][2]]['name']=$v['path'][3];}print_r($ar);

忘记说了,$arr数组中的 每个元素的 path 下的元素数量是不同的,有可能就像上面只有4个元素,也有可能只有1个或2个,也有可能有N个.

$ar = array(  '0' => Array(    'size' => 123,    'path' => Array(      '0' => 'a',      '1' => 'b',      '2' => 'c',      '3' => 'abc',      )    ),  '1' => Array(    'size' => 456,    'path' => Array(      '0' => 'd',      '1' => 'e',      '2' => 'f',      '3' => 'def',      )    ));foreach($ar as $item) {  $t = array();  $p =& $t;  foreach($item['path'] as $i=>$k) {    if(strlen($k) > 1) { //注      $item['path'] = $k;      $p = $item;      break;    }    $p[$k] = array();    $p =& $p[$k];    unset($item['path'][$i]);  }  $res[] = $t;}print_r($res);/*注：这个结束条件太牵强，但你又没有给出结束条件，只能观察结果勉强为之不过是个引用的练习罢了*/

Array(    [0] => Array        (            [a] => Array                (                    [b] => Array                        (                            [c] => Array                                (                                    [size] => 123                                    [path] => abc                                )                        )                )        )    [1] => Array        (            [d] => Array                (                    [e] => Array                        (                            [f] => Array                                (                                    [size] => 456                                    [path] => def                                )                        )                )        ))

多谢啦,对PHP不是很熟悉