在input 中按回车如何把焦点定位到linkbutton上？_html/css_WEB-ITnose

代码如下：    
    $( '#password').textbox('textbox' ).keydown(function (e) {
                if (e.keyCode == 13) {
                   $( "#login").linkbutton('linkbutton' ).focus();
                }
            });  

回复讨论(解决方案)

      
        

  
              
          
          
            

  
                  
                      
                          
                      
                      
                          
                      
                

Username:
Password:

  
            

  
          
      
    <script> <br /> var usernameObj = document.getElementById("username"); <br /> usernameObj.onkeydown = function(event) { <br /> e = event ? event :(window.event ? window.event : null); <br /> // 按下回车键且输入框值非空时 <br /> if(e.keyCode==13 && usernameObj.value){ <br /> document.getElementById("password").focus(); <br /> } <br /> } <br /> </script>    

参考 http://blog.csdn.net/magi1201/article/details/45177113

focus()是jquery对象的方法，
$( "#login").linkbutton('linkbutton' )返回的不是jquery对象

我猜应该是这样：$( "#login").focus()