Codeforces Round #281 (Div. 2) (A、B、C、D题)_html/css_WEB-ITnose

WBOY
发布: 2016-06-24 11:52:51
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996 人浏览过

昨天这场CF打的还挺爽的,不过就是没咋涨Rating,没把握好涨Rating的机会。。

本来可以过四题的,,但是很失败,重评后跪了两道。。唉:-(



A. Vasya and Football

思路:给每个人计数,黄牌+1,红牌+2。

当数字第一次超过2时输出。


题目链接:A. Vasya and Football


AC代码:

#include <cstdio>#include <cstring>#include <iostream>#include <algorithm>#include <string>#include <cmath>using namespace std;struct node {	char name[25];	int a[105];}home, away;int main(){	for(int i=0; i  <br>  <br>  <p></p>  <p><br> </p>  <p></p>  <p><strong>B. Vasya and Wrestling</strong></p>  <p><strong>思路:先用sum是否为0判断分高的,sum>0 => first, sum second,</strong></p>  <p><strong>sum=0则相同,再判断字典序,如果再相同则判断最后一次动作。</strong></p>  <p><strong>注意sum需要long long。</strong></p>  <strong><br> </strong>  <p><strong>题目链接:B. Vasya and Wrestling</strong></p>  <p><strong><br> </strong></p>  <strong>AC代码:</strong>  <p><br> </p>  <p></p>  <pre name="code" class="sycode">#include <cstdio>#include <cstring>#include <iostream>#include <algorithm>#include <string>#include <cmath>using namespace std;int judge(int a[], int b[], int na, int nb){	int i, j;	for(i=0, j=0; i<na j i if>b[i])return 1;		else if(a[i]<b if else main long sum="0;" int n a b na="0," nb="0;" scanf t for i="0;">0)a[na++] = t;		else if(t0)printf("first\n");	else if(sum0)printf("first\n");	else if(judge(a,b,na,nb)==2&&t  <br>  <br>  </b><p></p>  <p><br> </p>  <p><strong>C. Vasya and Basketball</strong><br> </p>  <p> </p>  <p><strong>思路:给所有球排序,先把全部都赋值为3,然后依次减为2,再判断其中间过程的MAX</strong></p>  <p><strong>昨天做题的时候有点小混乱。。</strong></p>  <p><strong><br> </strong></p>  <p><strong>题目链接:C. Vasya and Basketball</strong></p>  <p><strong><br> </strong></p>  <p><strong>AC代码:</strong></p>  <p><br> </p>  <p></p>  <pre name="code" class="sycode">#include <cstdio>#include <cstring>#include <iostream>  #include <queue>  #include <map>  #include <set>  #include <vector>  #include <algorithm>   using namespace std;    #define LL long long  #define INF 0xfffffffpair<int> p[400010];int main(){    int n, m;    scanf("%d", &n);    for(int i=0; i<n i scanf p for sort int as="n*3," bs="m*3," ansa ansb max="-0xfffffff;" if>MAX)			{                MAX=as-bs;                ansa=as;                ansb=bs;            }        }        if(p[i].second==1) as--;		else bs--;    }    printf("%d:%d\n", ansa, ansb);    return 0;}</n></int></algorithm></vector></set></map></queue></iostream></cstring></cstdio>
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D. Vasya and Chess

思路:貌似这题有点水。。


题目链接:D. Vasya and Chess


AC代码:


#include <cstdio>#include <cstring>#include <iostream>#include <algorithm>#include <string>#include <cmath>using namespace std;int main(){	int n;	scanf("%d", &n);	if(n%2==1)		printf("black\n");	else if(n%2==0)	{		printf("white\n1 2\n");	}	return 0;}</cmath></string></algorithm></iostream></cstring></cstdio>
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