关于jq的delegate问题

WBOY
发布: 2016-09-05 08:59:59
原创
1540 人浏览过

<code>//PHP
<?php include "db.php";
if(isset($_POST["category"])){


    $category_query = "SELECT * FROM categories";


    $run_query = mysqli_query($con,$category_query); 
    echo "
<div class='nav nav-pills nav-stacked'>
    <li class="active"><a href="#"><h4>Categories</h4></a></li>
    ";

    if(mysqli_num_rows($run_query)>0){
        
        while($row = mysqli_fetch_array($run_query)){
            $cid = $row["cat_id"];
            $cat_name = $row["cat_title"];

//问题在这里
            echo "
<li><a href="#" class="category" cid="$cid">$cat_name</a></li>
            ";
        }
        echo "";
    }
}


if(isset($_POST["brand"])){
    $brand_query = "SELECT * FROM brands";
    $run_query = mysqli_query($con,$brand_query);
    echo "
<div class="nav nav-pills nav-stacked">
    <li class="active"><a href="#"><h4>Brands</h4></a></li>
    ";

    if(mysqli_num_rows($run_query)>0){
        while($row = mysqli_fetch_array($run_query)){
            $bid = $row["brand_id"];
            $brand_name = $row["brand_title"];
            echo "
<li><a href="#">$brand_name</a></li>
            ";
        }
        echo "</div>";
    }
}

if(isset($_POST["getProduct"])){
    $product_query =  "SELECT * FROM products ORDER BY RAND() LIMIT 0,9";
    $run_query = mysqli_query($con,$product_query);
    if(mysqli_num_rows($run_query) >0 ){
        while($row = mysqli_fetch_array($run_query)){
           $pro_id = $row['product_id'];
           $pro_cat = $row['product_cat'];
           $pro_brand = $row['product_brand'];
           $pro_title = $row['product_title'];
           $pro_price = $row['product_price'];
           $pro_image = $row['product_image'];
           echo "
             <div class="col-md-4">
                        <div class="panel panel-info">
                            <div class="panel-heading">$pro_title</div>
                            <div class="panel-body">
                                <img    style="max-width:90%" src="product_image/%24pro_image" alt="关于jq的delegate问题" >
                            </div>
                            <div class="panel-heading">$.$pro_price.00
                              <button pid="$pro_id" style="float:right" class="btn btn-danger btn-xs">AddToCart</button>
                            </div>
                        </div>
                        </div>
           ";
        }
    }

}


?></code>
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<code>//JS

 $(document).ready(function() {
    cat();
    brand();
    product();

    function cat() {
        $.ajax({
                url: 'action.php',
                type: 'POST',
                data: {
                    category: 1
                },
            })
            .done(function(data) {
                //console.log(data);
                $("#get_category").html(data);

            });


    }

    function brand() {
        $.ajax({
                url: 'action.php',
                type: 'POST',
                data: {
                    brand: 1
                },
            })
            .done(function(data) {
                //console.log(data);

                $("#get_brand").html(data);

            });


    }


    function product() {
        $.ajax({
                url: 'action.php',
                type: 'POST',
                data: {
                    getProduct: 1
                },
            })
            .done(function(data) {
                //console.log(data);
                $("#get_product").html(data);

            });
    }

    //使用 delegate() 方法。on不能获取
    $("body").delegate(".category", "click", function() {
        alert(123);
    })
    // $(".category").on("click", function(event) {
    //     alert(13);
    // });
})</code>
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我用on的方法为什么点击没反应?而delegate却有?是不是因为这个class写在php上,on不能读取?还是怎么样?

回复内容:

<code>//PHP
<?php include "db.php";
if(isset($_POST["category"])){


    $category_query = "SELECT * FROM categories";


    $run_query = mysqli_query($con,$category_query); 
    echo "
<div class='nav nav-pills nav-stacked'>
    <li class="active"><a href="#"><h4>Categories</h4></a></li>
    ";

    if(mysqli_num_rows($run_query)>0){
        
        while($row = mysqli_fetch_array($run_query)){
            $cid = $row["cat_id"];
            $cat_name = $row["cat_title"];

//问题在这里
            echo "
<li><a href="#" class="category" cid="$cid">$cat_name</a></li>
            ";
        }
        echo "";
    }
}


if(isset($_POST["brand"])){
    $brand_query = "SELECT * FROM brands";
    $run_query = mysqli_query($con,$brand_query);
    echo "
<div class="nav nav-pills nav-stacked">
    <li class="active"><a href="#"><h4>Brands</h4></a></li>
    ";

    if(mysqli_num_rows($run_query)>0){
        while($row = mysqli_fetch_array($run_query)){
            $bid = $row["brand_id"];
            $brand_name = $row["brand_title"];
            echo "
<li><a href="#">$brand_name</a></li>
            ";
        }
        echo "</div>";
    }
}

if(isset($_POST["getProduct"])){
    $product_query =  "SELECT * FROM products ORDER BY RAND() LIMIT 0,9";
    $run_query = mysqli_query($con,$product_query);
    if(mysqli_num_rows($run_query) >0 ){
        while($row = mysqli_fetch_array($run_query)){
           $pro_id = $row['product_id'];
           $pro_cat = $row['product_cat'];
           $pro_brand = $row['product_brand'];
           $pro_title = $row['product_title'];
           $pro_price = $row['product_price'];
           $pro_image = $row['product_image'];
           echo "
             <div class="col-md-4">
                        <div class="panel panel-info">
                            <div class="panel-heading">$pro_title</div>
                            <div class="panel-body">
                                <img    style="max-width:90%" src="product_image/%24pro_image" alt="关于jq的delegate问题" >
                            </div>
                            <div class="panel-heading">$.$pro_price.00
                              <button pid="$pro_id" style="float:right" class="btn btn-danger btn-xs">AddToCart</button>
                            </div>
                        </div>
                        </div>
           ";
        }
    }

}


?></code>
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<code>//JS

 $(document).ready(function() {
    cat();
    brand();
    product();

    function cat() {
        $.ajax({
                url: 'action.php',
                type: 'POST',
                data: {
                    category: 1
                },
            })
            .done(function(data) {
                //console.log(data);
                $("#get_category").html(data);

            });


    }

    function brand() {
        $.ajax({
                url: 'action.php',
                type: 'POST',
                data: {
                    brand: 1
                },
            })
            .done(function(data) {
                //console.log(data);

                $("#get_brand").html(data);

            });


    }


    function product() {
        $.ajax({
                url: 'action.php',
                type: 'POST',
                data: {
                    getProduct: 1
                },
            })
            .done(function(data) {
                //console.log(data);
                $("#get_product").html(data);

            });
    }

    //使用 delegate() 方法。on不能获取
    $("body").delegate(".category", "click", function() {
        alert(123);
    })
    // $(".category").on("click", function(event) {
    //     alert(13);
    // });
})</code>
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我用on的方法为什么点击没反应?而delegate却有?是不是因为这个class写在php上,on不能读取?还是怎么样?

对于动态生成的元素使用on

<code> $('body').on('click','.category' , function() {
         alert(123);
     })</code>
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在你用一个新 API 之前,应通过文档充分了解它的作用。

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