SQL实现根据类型对金额进行归类

select
temp.id
,sum(temp.typyA_amount) as typyA_amount
,sum(temp.typyB_amount) as typyB_amount
,sum(temp.typyC_amount) as typyC_amount
,sum(temp.typyD_amount) as typyD_amount
from
  (select t.id
  ,sum(t.A) as typyA_amount  --A
  ,null as typyB_amount --B
  ,null as typyC_amount --C
  ,null as typyD_amount --D
  from table t
  where t.type ='A'
  group by t.id
  union all
  select t.id
  ,null as typyA_amount  --A
  ,sum(t.B) as typyB_amount --B
  ,null as typyC_amount --C
  ,null as typyD_amount --D
  from table t
  where t.type ='B'
  group by t.id
  union all
  select t.id
  ,null as typyA_amount  --A
  ,null as typyB_amount --B
  ,sum(t.C) as typyC_amount --C
  ,null as typyD_amount --D
  from table t
  where t.type ='C'
  group by t.id
  union all
  select t.id
  ,null as typyA_amount  --A
  ,null as typyB_amount --B
  ,null as typyC_amount --C
  ,sum(t.D) as typyD_amount --D
  from table t
  where t.type ='D'
  group by t.id) temp