首页 > 后端开发 > C#.Net教程 > 用.Net调用GoogleAPI获取Google Task列表失败

用.Net调用GoogleAPI获取Google Task列表失败

巴扎黑
发布: 2016-12-20 09:22:06
原创
1942 人浏览过

代码如下

static void Main(string[] args)
        {
            // Register the authenticator. The Client ID and secret have to be copied from the API Access
            // tab on the Google APIs Console.
            var provider = new NativeApplicationClient(GoogleAuthenticationServer.Description);
            provider.ClientIdentifier = "272908629865.apps.googleusercontent.com";
            provider.ClientSecret = "4UmdiNDILOV5bv-qRQz2XUwA";
            var auth = new OAuth2Authenticator<NativeApplicationClient>(provider, GetAuthentication);
            // Create the service and register the previously created OAuth2 Authenticator.
            var service = new TasksService(auth);
            TaskLists results = service.Tasklists.List().Fetch();
            foreach (TaskList list in results.Items)
            {
                Console.WriteLine(list.Title);
            }
        }
        private static IAuthorizationState GetAuthentication(NativeApplicationClient arg)
        {
            // Get the auth URL:
            IAuthorizationState state = new AuthorizationState(new[] { TasksService.Scopes.Tasks.ToString() });
            state.Callback = new Uri(NativeApplicationClient.OutOfBandCallbackUrl);
            Uri authUri = arg.RequestUserAuthorization(state);
            // Request authorization from the user (by opening a browser window):
            Process.Start(authUri.ToString());
            Console.Write("  Authorization Code: ");
            string authCode = Console.ReadLine();
            Console.WriteLine();
            // Retrieve the access token by using the authorization code:
            return arg.ProcessUserAuthorization(authCode, state);
        }
登录后复制

运行

Process.Start(authUri.ToString());时浏览器里面的结果是:

OAuth2.0 错误:invalid_scope

You can email the developer of this application at:jipen...@gmail.com

Some requested scopes were invalid. {invalid=[Tasks]}

   


来源:php.cn
本站声明
本文内容由网友自发贡献,版权归原作者所有,本站不承担相应法律责任。如您发现有涉嫌抄袭侵权的内容,请联系admin@php.cn
热门教程
更多>
最新下载
更多>
网站特效
网站源码
网站素材
前端模板