首页 > Java > java教程 > 正文

Java 实例 - 利用堆栈将中缀表达式转换成后缀表达式

黄舟
发布: 2017-01-22 15:20:54
原创
1968 人浏览过

以下实例演示了如何使用堆栈进行表达式的堆栈将中缀(Infix)表达式转换成后缀(postfix)表达式:

/*
 author by w3cschool.cc
 InToPost.java
 */import java.io.IOException;public class InToPost {
   private Stack theStack;
   private String input;
   private String output = "";
   public InToPost(String in) {
      input = in;
      int stackSize = input.length();
      theStack = new Stack(stackSize);
   }
   public String doTrans() {
      for (int j = 0; j < input.length(); j++) {
         char ch = input.charAt(j);
         switch (ch) {
            case &#39;+&#39;: 
            case &#39;-&#39;:
            gotOper(ch, 1); 
            break; 
            case &#39;*&#39;: 
            case &#39;/&#39;:
            gotOper(ch, 2); 
            break; 
            case &#39;(&#39;: 
            theStack.push(ch);
            break;
            case &#39;)&#39;: 
            gotParen(ch); 
            break;
            default: 
            output = output + ch; 
            break;
         }
      }
      while (!theStack.isEmpty()) {
         output = output + theStack.pop();
      }
      System.out.println(output);
      return output; 
   }
   public void gotOper(char opThis, int prec1) {
      while (!theStack.isEmpty()) {
         char opTop = theStack.pop();
         if (opTop == &#39;(&#39;) {
            theStack.push(opTop);
            break;
         }
         else {
            int prec2;
            if (opTop == &#39;+&#39; || opTop == &#39;-&#39;)
            prec2 = 1;
            else
            prec2 = 2;
            if (prec2 < prec1) { 
               theStack.push(opTop);
               break;
            }
            else
            output = output + opTop;
         }
      }
      theStack.push(opThis);
   }
   public void gotParen(char ch){ 
      while (!theStack.isEmpty()) {
         char chx = theStack.pop();
         if (chx == &#39;(&#39;) 
         break; 
         else
         output = output + chx; 
      }
   }
   public static void main(String[] args) 
   throws IOException {
      String input = "1+2*4/5-7+3/6";
      String output;
      InToPost theTrans = new InToPost(input);
      output = theTrans.doTrans(); 
      System.out.println("Postfix is " + output + &#39;\n&#39;);
   }
   class Stack {
      private int maxSize;
      private char[] stackArray;
      private int top;
      public Stack(int max) {
         maxSize = max;
         stackArray = new char[maxSize];
         top = -1;
      }
      public void push(char j) {
         stackArray[++top] = j;
      }
      public char pop() {
         return stackArray[top--];
      }
      public char peek() {
         return stackArray[top];
      }
      public boolean isEmpty() {
         return (top == -1);
     }
   }}
登录后复制

以上代码运行输出结果为:

124*5/+7-36/+Postfix is 124*5/+7-36/+
登录后复制

以上就是Java 实例 - 利用堆栈将中缀表达式转换成后缀表达式的内容,更多相关内容请关注PHP中文网(www.php.cn)!

来源:php.cn
本站声明
本文内容由网友自发贡献,版权归原作者所有,本站不承担相应法律责任。如您发现有涉嫌抄袭侵权的内容,请联系admin@php.cn
热门教程
更多>
最新下载
更多>
网站特效
网站源码
网站素材
前端模板