将图片读入到Dom中,并将其存为xml文件
1、需要命名空间
using System.Text;
using System.IO;
using System.Xml;
2、文件夹中存在001.jpg图片
3、生成一个docSave.xml文件
//********************************* { XmlDocument myXmlDoc = new XmlDocument(); myXmlDoc.LoadXml("<picture><name>picture</name></picture>"); XmlElement elem = myXmlDoc.CreateElement("image"); // 打开图片文件,利用该图片构造一个文件流 FileStream fs = new FileStream("../../001.jpg",FileMode.Open); // 使用文件流构造一个二进制读取器将基元数据读作二进制值 BinaryReader br = new BinaryReader(fs); byte[] imageBuffer = new byte[br.BaseStream.Length]; br.Read(imageBuffer,0,Convert.ToInt32(br.BaseStream.Length)); string textString = System.Convert.ToBase64String(imageBuffer); fs.Close(); br.Close(); XmlText text = myXmlDoc.CreateTextNode(textString); myXmlDoc.DocumentElement.AppendChild(elem); myXmlDoc.DocumentElement.LastChild.AppendChild(text); myXmlDoc.Save("../../docSave.xml"); MessageBox.Show("读写结束!"); catch(Exception ex) { MessageBox.Show(ex.ToString()); } //************************************************ //生成后的Xml文档 //****** <picture> <name>picture</name> <image>......</image> </picture> //************************************************* //测试上一程序 //***********
说明:读取docSave.xml中的image节点,将其存为图片格式002.jpg.
try { int readByte = 0; int bytesToRead = 1044; XmlTextReader xmlTxtRd = new XmlTextReader("../../docSave.xml"); FileStream fs = new FileStream("../../002.jpg",FileMode.Create); BinaryWriter bw = new BinaryWriter(fs); byte[] base64buffer = new byte[bytesToRead]; while(xmlTxtRd.Read()) { if (xmlTxtRd.NodeType == XmlNodeType.Element && xmlTxtRd.Name == "image") { do { readByte = xmlTxtRd.ReadBase64(base64buffer,0,bytesToRead); bw.Write(base64buffer,0,readByte); } while( bytesToRead<= readByte); } } bw.Flush(); bw.Close(); fs.Close(); xmlTxtRd.Close(); MessageBox.Show("读写结束!"); } catch(Exception ex) { MessageBox.Show(ex.ToString()); }
以上就是将图片读入到Dom中,并将其存为xml文件的内容,更多相关内容请关注PHP中文网(www.php.cn)!