学习编程、学习Python最好的方式就是练习，哪怕是新手，只要不断地敲代码输出，肯定会有神效。
Python的练手项目很多，特别是Github上，建议不管新手、老司机都去看看。
这里推荐给大家一个Gitthub上练习的项目，算法仓库-algorithms。
https://github.com/keon/algorithms
这里面集合众多核心算法的Python实现，比如排序、图计算、回溯、队列、流计算、堆、搜索、压缩等等。
该仓库支持第三方库安装，在python中进行调用，非常方便。
首先使用pip进行安装：
pip3 install algorithms
然后导入相关模块进行调用，比如sort模块里的merge_sort归并排序算法。
from algorithms.sort import merge_sort if __name__ == "__main__": my_list = [1, 8, 3, 5, 6] my_list = merge_sort(my_list) print(my_list)
举几个常见的算法案例。
def bucket_sort(arr): ''' Bucket Sort Complexity: O(n^2) The complexity is dominated by nextSort ''' # The number of buckets and make buckets num_buckets = len(arr) buckets = [[] for bucket in range(num_buckets)] # Assign values into bucket_sort for value in arr: index = value * num_buckets // (max(arr) + 1) buckets[index].append(value) # Sort sorted_list = [] for i in range(num_buckets): sorted_list.extend(next_sort(buckets[i])) return sorted_list def next_sort(arr): # We will use insertion sort here. for i in range(1, len(arr)): j = i - 1 key = arr[i] while arr[j] > key and j >= 0: arr[j+1] = arr[j] j = j - 1 arr[j + 1] = key return arr
import math
def distance(x,y):
"""[summary]
HELPER-FUNCTION
calculates the (eulidean) distance between vector x and y.
Arguments:
x {[tuple]} -- [vector]
y {[tuple]} -- [vector]
"""
assert len(x) == len(y), "The vector must have same length"
result = ()
sum = 0
for i in range(len(x)):
result += (x[i] -y[i],)
for component in result:
sum += component**2
return math.sqrt(sum)
def nearest_neighbor(x, tSet):
"""[summary]
Implements the nearest neighbor algorithm
Arguments:
x {[tupel]} -- [vector]
tSet {[dict]} -- [training set]
Returns:
[type] -- [result of the AND-function]
"""
assert isinstance(x, tuple) and isinstance(tSet, dict)
current_key = ()
min_d = float('inf')
for key in tSet:
d = distance(x, key)
if d < min_d:
min_d = d
current_key = key
return tSet[current_key]# Implement the encode and decode methods.
def encode(strs):
"""Encodes a list of strings to a single string.
:type strs: List[str]
:rtype: str
"""
res = ''
for string in strs.split():
res += str(len(string)) + ":" + string
return res
def decode(s):
"""Decodes a single string to a list of strings.
:type s: str
:rtype: List[str]
"""
strs = []
i = 0
while i < len(s):
index = s.find(":", i)
size = int(s[i:index])
strs.append(s[index+1: index+1+size])
i = index+1+size
return strsdef get_histogram(input_list: list) -> dict:
"""
Get histogram representation
:param input_list: list with different and unordered values
:return histogram: dict with histogram of input_list
"""
# Create dict to store histogram
histogram = {}
# For each list value, add one to the respective histogram dict position
for i in input_list:
histogram[i] = histogram.get(i, 0) + 1
return histogram个人感觉这个仓库里的算法很齐全，适合做练习，小伙伴们可以试试。
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