为了使其理解,我们正在使用以下表中的数据 −
mysql> Select * from customers; +-------------+----------+ | Customer_Id | Name | +-------------+----------+ | 1 | Rahul | | 2 | Yashpal | | 3 | Gaurav | | 4 | Virender | +-------------+----------+ 4 rows in set (0.00 sec) mysql> Select * from reserve; +------+------------+ | ID | Day | +------+------------+ | 1 | 2017-12-30 | | 2 | 2017-12-28 | | 2 | 2017-12-25 | | 1 | 2017-12-24 | | 3 | 2017-12-26 | +------+------------+ 5 rows in set (0.00 sec)
现在,以下是一个子查询,将找到所有没有预订任何汽车的客户的姓名。
mysql> Select Name from customers where customer_id NOT IN (Select id From reserve); +----------+ | Name | +----------+ | Virender | +----------+ 1 row in set (0.00 sec)
现在,通过以下步骤,我们可以将上述子查询转换为RIGHT JOIN −
mysql> SELECT Name from customers LEFT JOIN reserve ON customer_id = Id WHERE Id IS NULL; +----------+ | Name | +----------+ | Virender | +----------+ 1 row in set (0.00 sec)
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