五维体数是帕斯卡三角形的任意一行中第五个数字,从左到右或从右到左开始,起始于5项行1 4 6 4 1。
这种数字的前几个是
1, 5, 15, 35, 70, 126, 210, 330, 495, 715, 1001, 1365
Pentatope numbers belong in the class of figurate numbers, which can be represented as regular, discrete geometric patterns. The formula for the nth pentatopic number is
$$left(begin{array}{c}n+3 4end{array}right)=left(frac{n(n+1)+(n+2)+(n+3)}{24}right)=left(frac{n^2}{4!}right)$$
Accept the Nth Term from the User to find the Pentotope Numbers.
Use the formula
$$left(begin{array}{c}n+3 4end{array}right)=left(frac{n(n+1)+(n+2)+(n+3)}{24}right)=left(frac{n^2}{4!}right)$$
/* Program to print pentatope numbers upto Nth term */ #include<stdio.h> int main() { int n, n1, nthterm, nthterm1, i; clrscr(); printf("</p><p> Please enter the nth term to print Pentatope: "); scanf("%d",&n); nthterm = n * (n + 1) * (n + 2) * (n + 3) / 24; printf("The Pentotpe Number is: "); printf("%d", nthterm); printf("</p><p></p><p>"); printf("Printing the Pentotope Numbers upto Nth Term"); printf("</p><p> Print Pentatope Numbers till the term: "); scanf("%d",&n1); printf("</p><p></p><p>"); printf("The Pentotope Numbers are:"); printf("</p><p></p><p>"); for (i = 1; i <= n1; i++){ nthterm1 = (i * (i + 1) * (i + 2) * (i + 3) / 24); printf("%d\t", nthterm1); } getch(); return 0; }
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