如何编写一个 MySQL 存储函数来更新表中的值？

众所周知，当我们想要返回结果时，最好使用函数。因此，当我们创建存储函数来操作表（例如插入或更新值）时，它或多或少类似于存储过程。在下面的示例中，我们将创建一个名为“tbl_update”的存储函数，它将更新名为“student_marks”的表中的值。

mysql> Select * from student_marks//
+---------+------+---------+---------+---------+
| Name    | Math | English | Science | History |
+---------+------+---------+---------+---------+
| Raman   |   95 |      89 |      85 |      81 |
| Rahul   |   90 |      87 |      86 |      81 |
| Mohit   |   90 |      85 |      86 |      81 |
| Saurabh | NULL |    NULL |    NULL |    NULL |
+---------+------+---------+---------+---------+
4 rows in set (0.00 sec)

mysql> Create Function tbl_Update(S_name Varchar(50),M1 INT,M2 INT,M3 INT,M4 INT)
    -> RETURNS INT
    -> DETERMINISTIC
    -> BEGIN
    -> UPDATE student_marks SET Math = M1,English = M2, Science = M3, History =M4 WHERE Name = S_name;
    -> RETURN 1;
    -> END //
Query OK, 0 rows affected (0.03 sec)

mysql> Select tbl_update('Saurabh',85,69,75,82);
+------------------------------------+
| tbl_update('Saurabh',85,69,75,82)  |
+------------------------------------+
|                                  1 |
+------------------------------------+
1 row in set (0.07 sec)

mysql> Select * from Student_marks;
+---------+------+---------+---------+---------+
| Name    | Math | English | Science | History |
+---------+------+---------+---------+---------+
| Raman   |   95 |      89 |      85 |      81 |
| Rahul   |   90 |      87 |      86 |      81 |
| Mohit   |   90 |      85 |      86 |      81 |
| Saurabh |   85 |      69 |      75 |      82 |
+---------+------+---------+---------+---------+
4 rows in set (0.00 sec)

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