C# 中的混合字典类？

HybridDictionary类通过使用ListDictionary在集合较小时实现IDictionary，然后在集合变大时切换到Hashtable。

以下是HybridDictionary类的属性：

序号	属性和描述
1	Count 获取包含的键/值对的数量

混合字典。

2 IsFixedSize

获取一个值，该值指示是否 HybridDictionary 具有固定大小。

3 IsReadOnly

获取一个值，指示 HybridDictionary 是否为 只读。

4 IsSynchronized

获取一个值，指示 HybridDictionary 是否为 synchronized (线程安全)。

5 Item[Object]

获取或设置与指定键关联的值。

6 Keys

获取包含键的 ICollection HybridDictionary。

7 SyncRoot

获取可用于同步访问的对象 到HybridDictionary。

8 Values

获取包含在HybridDictionary中的值的ICollection the HybridDictionary.

以下是HybridDictionary类的一些方法：

序号	方法和描述
1	Add(Object, Object) 将具有指定键和值的条目添加到 the HybridDictionary.
2	Clear() 从HybridDictionary中移除所有条目。
3	Contains(Object) 确定HybridDictionary是否包含特定的键。
4	CopyTo(Array, Int32) 将HybridDictionary的条目复制到一个一维数组中 在指定索引处的数组实例。
5	Equals(Object) 确定指定的对象是否等于 当前对象。 (Inherited from Object)
6	GetEnumerator() 返回一个 IDictionaryEnumerator，用于遍历 HybridDictionary。
7	GetHashCode() strong> 用作默认哈希函数。 （继承自Object）
8	GetType() 获取当前实例的Type。 (Inherited from Object)

要计算HybridDictionary中键值对的数量，代码如下 −

示例

现在让我们看一些示例 −

 演示

using System;
using System.Collections;
using System.Collections.Specialized;
public class Demo {
   public static void Main() {
      HybridDictionary dict1 = new HybridDictionary();
      dict1.Add("A", "SUV");
      dict1.Add("B", "MUV");
      dict1.Add("C", "AUV");
      Console.WriteLine("HybridDictionary1 elements...");
      foreach(DictionaryEntry d in dict1) {
         Console.WriteLine(d.Key + " " + d.Value);
      }
      Console.WriteLine("Count of Key/value pairs in Dictionary1 = "+dict1.Count);
      HybridDictionary dict2 = new HybridDictionary();
      dict2.Add("1", "One");
      dict2.Add("2", "Two");
      dict2.Add("3", "Three");
      dict2.Add("4", "Four");
      dict2.Add("5", "Five");
      dict2.Add("6", "Six");
      Console.WriteLine("HybridDictionary2 elements...");
      foreach(DictionaryEntry d in dict2) {
         Console.WriteLine(d.Key + " " + d.Value);
      }
      Console.WriteLine("Count of Key/value pairs in Dictionary2 = "+dict1.Count);
      dict2.Clear();
      Console.WriteLine("Count of Key/value pairs in Dictionary2 (Updated) = "+dict2.Count);
   }
}

输出

这将产生以下输出 −

HybridDictionary1 elements...
A SUV
B MUV
C AUV
Count of Key/value pairs in Dictionary1 = 3
HybridDictionary2 elements...
1 One
2 Two
3 Three
4 Four
5 Five
6 Six
Count of Key/value pairs in Dictionary2 = 3
Count of Key/value pairs in Dictionary2 (Updated) = 0

要检查HybridDictionary是否已同步，代码如下 −

示例

 实时演示

using System;
using System.Collections;
using System.Collections.Specialized;
public class Demo {
   public static void Main() {
      HybridDictionary dict1 = new HybridDictionary();
      dict1.Add("A", "Books");
      dict1.Add("B", "Electronics");
      dict1.Add("C", "Smart Wearables");
      dict1.Add("D", "Pet Supplies");
      dict1.Add("E", "Clothing");
      dict1.Add("F", "Footwear");
      Console.WriteLine("HybridDictionary1 elements...");
      foreach(DictionaryEntry d in dict1) {
         Console.WriteLine(d.Key + " " + d.Value);
      }
      Console.WriteLine("Is the HybridDictionary1 having fixed size? = "+dict1.IsFixedSize);
      Console.WriteLine("If HybridDictionary1 read-only? = "+dict1.IsReadOnly);
      Console.WriteLine("Is HybridDictionary1 synchronized = "+dict1.IsSynchronized);
      HybridDictionary dict2 = new HybridDictionary();
      dict2.Add("1", "One");
      dict2.Add("2", "Two");
      dict2.Add("3", "Three");
      dict2.Add("4", "Four");
      dict2.Add("5", "Five");
      dict2.Add("6", "Six");
      Console.WriteLine("HybridDictionary2 elements...");
      foreach(DictionaryEntry d in dict2) {
         Console.WriteLine(d.Key + " " + d.Value);
      }
      Console.WriteLine("Is HybridDictionary1 equal to HybridDictionary2? = "+(dict1.Equals(dict2)));
      Console.WriteLine("Is the HybridDictionary2 having fixed size? = "+dict2.IsFixedSize);
      Console.WriteLine("If HybridDictionary2 read-only? = "+dict2.IsReadOnly);
      Console.WriteLine("Is HybridDictionary2 synchronized = "+dict2.IsSynchronized);
   }
}

输出

这将产生以下输出 −

HybridDictionary1 elements...
A Books
B Electronics
C Smart Wearables
D Pet Supplies
E Clothing
F Footwear
Is the HybridDictionary1 having fixed size? = False
If HybridDictionary1 read-only? = False
Is HybridDictionary1 synchronized = False
HybridDictionary2 elements...
1 One
2 Two
3 Three
4 Four
5 Five
6 Six
Is HybridDictionary1 equal to HybridDictionary2? = False
Is the HybridDictionary2 having fixed size? = False
If HybridDictionary2 read-only? = False
Is HybridDictionary2 synchronized = False

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