Js和JQuery获取鼠标指针坐标的实现代码分享_javascript技巧
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发布： 2016-05-16 15:57:41
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
<title>jquery 获取鼠标指针的坐标</title>
<script>
//普通js函数
function test(event) {
event = event || window.event;
var x = event.offsetX || event.layerX;
var y = event.offsetY || event.layerY;
alert("x="+x+"; y="+y);
}
//jquery函数
$(function(){
$("#t").mouseover(
function(event){
event = event || window.event;
var x = event.offsetX || event.originalEvent.layerX;
var y = event.offsetY || event.originalEvent.layerY;
alert("x:"+x+"; y:"+y);
}
);
});
</script>
</head>
<body>
<div id="t" style="float:left;background-color: green;width: 300px;height: 60px;">测试鼠标位置（jquery函数处理）</div>
<div id="s" onmouseover="test(event)" style="float:left;background-color: red;width: 300px;height: 60px;margin-left:10px;">测试鼠标位置（普通js函数处理）</div>
</body>
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