本文实例讲述了javascript自定义右键弹出菜单实现方法。分享给大家供大家参考。具体实现方法如下：
<head runat="server">
<title>无标题页</title>
<script type="text/javascript">
var oPopup = window.createPopup();
function PopMenu(id)
{
var oPopBody = oPopup.document.body;
oPopBody.style.backgroundColor = "buttonface";
oPopBody.style.border = "solid black 1px";
var TableBegin="<table style=\"border: 0; width: 100%; font-size: 12px;\" cellpadding=\"0\" cellspacing=\"0\">";
var Tr1="<tr><td valign=\"middle\" style=\"height: 20px;\" onmousemove=\"this.bgColor='highlight';this.style.color='highlighttext'\" onmouseout=\"this.bgColor='';this.style.color=''\" onclick=\"parent.window.open('/news/view.asp?id="+id+"');\">查看新闻</td></tr>";
var TrBr1="<tr><td style=\"background-color: ThreeDShadow; height: 1px;\"></td></tr>";
var Tr2="<tr><td valign=\"middle\" style=\"height: 20px;cursor:hand;\" onmousemove=\"this.bgColor='highlight';this.style.color='highlighttext'\" onmouseout=\"this.bgColor='';this.style.color=''\" onclick=\"parent.document.frames['main'].location='divdiv.aspx?id="+id+";'\">查看新闻</td></tr>";
var TableEnd="</table>";
oPopBody.innerHTML =TableBegin+Tr1+TrBr1+Tr2+TableEnd;
oPopup.show(event.x, event.y, 90, 41, document.body);
return false;
}
</script>
</head>
<body>
<form id="form1" runat="server">
<div>
<a href='javascript:void(0);' oncontextmenu='PopMenu(1);return false;'>
<img alt="" src='1.gif' style="max-width:90%"/>
<br/>
</a>
<iframe name="main" frameborder="0" width="100%" scrolling="auto" height="100%">
</iframe>
</div>
</form>
</body>
</html>希望本文所述对大家的javascript程序设计有所帮助。
