本文实例讲述了javascript自定义右键弹出菜单实现方法。分享给大家供大家参考。具体实现方法如下:
<head runat="server"> <title>无标题页</title> <script type="text/javascript"> var oPopup = window.createPopup(); function PopMenu(id) { var oPopBody = oPopup.document.body; oPopBody.style.backgroundColor = "buttonface"; oPopBody.style.border = "solid black 1px"; var TableBegin="<table style=\"border: 0; width: 100%; font-size: 12px;\" cellpadding=\"0\" cellspacing=\"0\">"; var Tr1="<tr><td valign=\"middle\" style=\"height: 20px;\" onmousemove=\"this.bgColor='highlight';this.style.color='highlighttext'\" onmouseout=\"this.bgColor='';this.style.color=''\" onclick=\"parent.window.open('/news/view.asp?id="+id+"');\">查看新闻</td></tr>"; var TrBr1="<tr><td style=\"background-color: ThreeDShadow; height: 1px;\"></td></tr>"; var Tr2="<tr><td valign=\"middle\" style=\"height: 20px;cursor:hand;\" onmousemove=\"this.bgColor='highlight';this.style.color='highlighttext'\" onmouseout=\"this.bgColor='';this.style.color=''\" onclick=\"parent.document.frames['main'].location='divdiv.aspx?id="+id+";'\">查看新闻</td></tr>"; var TableEnd="</table>"; oPopBody.innerHTML =TableBegin+Tr1+TrBr1+Tr2+TableEnd; oPopup.show(event.x, event.y, 90, 41, document.body); return false; } </script> </head> <body> <form id="form1" runat="server"> <div> <a href='javascript:void(0);' oncontextmenu='PopMenu(1);return false;'> <img alt="" src='1.gif' style="max-width:90%"/> <br/> </a> <iframe name="main" frameborder="0" width="100%" scrolling="auto" height="100%"> </iframe> </div> </form> </body> </html>
希望本文所述对大家的javascript程序设计有所帮助。