php
刚开始学php，写了一段文字生成图片的代码。现在发现不能将text传至php里，而且就算不传参。直接在php里定义$ment = $_POST['text'_] 也会报错：图像xxx因存在错误无法显示，肯定不是字体的问题，我快疯了..谁能帮帮我...代码如下
index.html:
<code> <title>Logo Generater</title> <form method="post" action="logo%20generate.php"> <label for="text">Company name:</label> <input type="text" name="text" id="text"> <input type="submit" name="submit" id="submit" value="OK"> </form> </code>
logo generate.php:
<code><?php $ment = 'What are you 弄啥类？'$ment = $_POST['text'];echo $ment;echo strlen($ment);$im = imagecreate(450,50);$white = imagecolorallocate($im,0,0,0);#imagecolortransparent($im,$white); $black = imagecolorallocate($im,255, 255,255);imagettftext($im,26,0,15,40,$black,'E:\xampp\htdocs\test\simsun.ttc',$ment);header("Content-type:image/png");imagepng($im);?></code>谢谢了...
-------------------------16:35更新-----------------------
谢谢帮助我的人~(づ￣ 3￣)づ
还有个问题 能不能像这张图一样，点击OK，传参给PHP，之后还在这个界面显示图片
以下是新代码~
<code> <title>Logo Generater</title> <form action="logo%20generate.php" method="post"> <h1>Logo Generater</h1> <h2>wirte by Yates WANG</h2> <label for="ment">Company name:</label> <input type="text" name="ment" id="ment"> <input type="submit" name="submit" id="submit" value="OK"> <br> <br> <img src="logo%20generate.php" alt="php 使用echo就报错...." > </form> <form> </form></code>
<code> <?php #$ment = 'What are you 弄啥类？';$ment = $_POST['ment'];#echo strlen($ment);#$len = strlen($ment) * 30;$im = imagecreate(400,50);$white = imagecolorallocate($im,0,0,0);#imagecolortransparent($im,$white); $black = imagecolorallocate($im,255, 255,255);imagettftext($im,26,0,15,40,$black,'C:\Windows\Fonts\simsun.ttc',$ment);header("Content-type:image/png");imagepng($im);imagedestroy($im);?></code>再次感谢！
