python比较2个xml内容的方法

本文实例讲述了python比较2个xml内容的方法。分享给大家供大家参考。具体分析如下：

from xml.etree import ElementTree
OK=True
main_pid = 10000
loop_depth = 0
def compare_xml(left, right, key_info='.'):
  global loop_depth
  loop_depth += 1
  if loop_depth == 1: print
  if left.tag != right.tag:
    print_diff(main_pid, key_info, 'difftag', left.tag, right.tag)
    return
  if left.text != right.text:
    print_diff(main_pid, key_info, 'difftext', left.text, right.text)
    return
  leftitems = dict(left.items())
  rightitems = dict(right.items())
  for k,v in leftitems.items():
    if k not in rightitems:
      s = '%s/%s' % (key_info, left.tag)
      print_diff(main_pid, s, 'lostattr', k, "")
  for k,v in rightitems.items():
    if k not in leftitems:
      s = '%s/%s' % (key_info, right.tag)
      print_diff(main_pid, s, 'extraattr', "", k)
  leftnodes = left.getchildren()
  rightnodes = right.getchildren()
  leftlen = len(leftnodes)
  rightlen = len(rightnodes)
  if leftlen != rightlen:
    s = '%s/%s' % (key_info, right.tag)
    print_diff(main_pid, s, 'difflen', leftlen, rightlen)
    return
  l = leftlen<rightlen and leftlen or rightlen
  d = {}
  for i in xrange(l):
    node=leftnodes[i]
    if node.tag not in d:
      d[node.tag] = 1
      tag = node.tag
    else:
      tag = node.tag + str(d[node.tag])
      d[node.tag] += 1
    s = '%s/%s' % (key_info, tag)
    compare_xml(leftnodes[i], rightnodes[i], s)
def print_diff(main_pid, key_info, msg, base_type, test_type):
  global OK
  info = u'[ %-5s ] %s -> %-40s [ %s != %s ]'%(msg.upper(), main_pid, key_info.strip('./'), base_type, test_type)
  print info.encode('gbk')
  OK = False

调用：

if __name__ == '__main__':
  s1 = '''''<&#63;xml version="1.0" encoding="UTF-8"&#63;> \
     <employees> \
     <employee id = '1'> \
      <name>linux</name>\
      <age>30</age>\
     </employee>\
     <employee id = '2'> \
      <name>windows</name>\
      <age>20</age>\
     </employee>\
     </employees>'''
  s2 = '''''<&#63;xml version="1.0" encoding="UTF-8"&#63;> \
     <employees> \
     <employee id = '3'> \
      <name>windows</name>\
      <age>20</age>\
     </employee>\
     <employee id = '4'> \
      <name>linux</name>\
      <age>30</age>\
     </employee>\
     </employees>'''
  lroot = ElementTree.fromstring(s1)
  rroot = ElementTree.fromstring(s2)
  compare_xml(lroot, rroot)

希望本文所述对大家的Python程序设计有所帮助。