Sencha touch 与PHP 怎么进行json 数据解析

ST 可以把数据包装成json式发送到php端 cartItemsStore = Ext.getStore('cartitemsconvert');var allData = [];cartItemsStore.each(function(records){allData.push(records.getData());});var dataToBeSentToServer = Ext.JSON.encode(allData);console.lo

ST 可以把数据包装成json格式发送到php端

cartItemsStore = Ext.getStore('cartitemsconvert');
				var allData = [];
				cartItemsStore.each(function(records){
					allData.push(records.getData());
				});
				var dataToBeSentToServer = Ext.JSON.encode(allData);
				console.log(dataToBeSentToServer);

然后用jsonp或是ajax将数据传输到PHP端

Ext.data.JsonP.request({
            		url: 'http://londit-50c03e41547f8.com.1130.url-test.com/dingcan/php/save-orders.php',
            		callbackKey: 'callback',
            		params: {
		                sendData:dataToBeSentToServer
            		},
            		timeout:2000,
            		success: function(result, request) {
	                	console.log('提交数据成功');
	            	}
        		});

然后PHP怎么获得这些json数据呢？红色部分是php的问题。如果不用stripslashes转换。stripslashes() 函数删除由 addslashes() 函数添加的反斜杠。否则数据打印出来是空，还有个解决办法就是：The fix was to turn off magic_quotes in php.ini. If you do this, you will no longer need the call to stripslashes(). 

$sendData = $_REQUEST['sendData'];
<span>$jsondata = stripslashes($sendData);</span>
//$sendData = '[{"id":"1","food":"\u5f20\u96ea\u6885","age":"27","subject":"\u8ba1\u7b97\u673a\u79d1\u5b66\u4e0e\u6280\u672f"},{"id":"2","food":"\u5f20\u6c9b\u9716","age":"21","subject":"\u8f6f\u4ef6\u5de5\u7a0b"}]';
$arrayData = json_decode($jsondata);
foreach($arrayData as $obj){
	echo "id：".$obj-&gt;food."<br>";
}

另外附上PHP两种解析json数据的方法：

在PHP代码中处理JSON 格式的字符串的两种方法：唯一不同已经highlight出来了

方法一：

$json ='[{"id":"1","name":"\u5f20\u96ea\u6885","age":"27","subject":"\u8ba1\u7b97\u673a\u79d1\u5b66\u4e0e\u6280\u672f"},{"id":"2","name":"\u5f20\u6c9b\u9716","age":"21","subject":"\u8f6f\u4ef6\u5de5\u7a0b"}]';
<span>$students = json_decode($json);//得到的是 object</span>
foreach($students as $obj){
echo "姓名：".$obj-&gt;name."年龄：".$obj-&gt;age." 专业：".$obj-&gt;subject."<br>";
}

方法二：

$json ='[{"id":"1","name":"\u5f20\u96ea\u6885","age":"27","subject":"\u8ba1\u7b97\u673a\u79d1\u5b66\u4e0e\u6280\u672f"},{"id":"2","name":"\u5f20\u6c9b\u9716","age":"21","subject":"\u8f6f\u4ef6\u5de5\u7a0b"}]';
<span>$students = json_decode($json, </span><span>true</span><span>);//得到的是 array</span>
for($i=0;$i<count echo></count>";
}