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(PHP 4, PHP 5, PHP 7)
easter_date — 得到指定年份的复活节午夜时的Unix时间戳。
$year
] )返回指定年份的复活节午夜时的Unix时间戳。
如果给定的年份超出Unix时间戳的范围(比如1970年以前或2037年以后),该函数将返回一个警告。
复活节的日期是由尼西亚议会在AD325年确定的为每年春分月圆后的第一个星期日。春分一般是在3月21日,这就简化为只要计算满月的日期和紧挨的星期日的日期。这里所用的算法是在532年由Dionysius Exiguus所介绍的,参考了Julian历法和Gregorian历法这两个历法来提高精确度。(在1753年以前用Julian历法计算,该历法是一个以19年为周期来确定月亮的相位的历法。在1753年以后用Gregorian历法计算,该历法由Clavius和Lilius发明,由Pope Gregory 8世在1582年推广)
year
1970年至2037年之间的数字形式的年份。
复活节日期的Unix时间戳。
版本 | 说明 |
---|---|
Since 4.3.0 | year 参数可选,缺省的默认值是当年。
|
Example #1 easter_date() example
<?php
echo date ( "M-d-Y" , easter_date ( 1999 )); // Apr-04-1999
echo date ( "M-d-Y" , easter_date ( 2000 )); // Apr-23-2000
echo date ( "M-d-Y" , easter_date ( 2001 )); // Apr-15-2001
?>
[#1] adwil at live dot com [2014-04-10 15:01:22]
Hey, recently I needed a function to get realization dates in online shop, so here it is (ready to go for polish users, please adjust your dates for any other country):
<?php
function getWorkday($date1,$workDays) {
$workDays = (int)$workDays;
if ($workDays <= 0)
return null;
$date1=strtotime('-1 day',strtotime($date1));
$lastYear = null;
$hol=array('01-01','01-06','05-01','05-03','08-15','11-01','11-11','12-25','12-26'); //array of month-date of static holidays (these are from Poland)
$i = 0;
while ($i<=$workDays) {
$year = date('Y', $date1);
if ($year !== $lastYear){
$lastYear = $year;
$easter = date('m-d', easter_date($year));
$date = strtotime($year . '-' . $easter); // easter
$easterSec = date('m-d', strtotime('+1 day', $date)); // easter monday
$greens = date('m-d', strtotime('+49 days', $date)); // zielone swiatki
$cc = date('m-d', strtotime('+60 days', $date)); // boze cialo
$hol[] = $easter;
$hol[] = $easterSec;
$hol[] = $greens;
$hol[] = $cc;
}
$weekDay=date('w',$date1);
if (!($weekDay==0 || $weekDay==6 || in_array(date('m-d',$date1),$hol)))
$i++;
$date1=strtotime('+1 day',$date1);
}
return date('Y-m-d',$date1);
}
?>
[#2] Guillaume Dufrene [2013-03-30 08:13:56]
I found a problem with holidays timestamp computation and daylight saving time.
An article about it at http://goo.gl/76t31 (in french only, sorry).
In summary, this year (2013) easter begins before adding an hour for daylight saving time (occured sunday at 3:00). It means that if you do $easter + X, where x is a number of seconds equivalent to one day, 39 days or 50 days, the result is not equals to a midnight timestamp...
Here a function to check if a midnight timestamp is equals to an holiday :
function isHoliday( $ts ) {
// Licence : Creative Commons (BY)
// By Webpulser - http://goo.gl/76t31
$fixed_holidays = array( ??01-01??, ??01-05??, ??08-05??, ??14-07??, ??15-08??, ??11-11??, ??25-12?? );
$format = ??d-m??;
$dm = date($format, $ts);
if ( in_array($dm, $fixed_holidays) ) return true;
$easter = easter_date( date(??Y??, $ts) );
if ( date($format, $easter + 86400) == $dm ) return true;
if ( date($format, $easter + 3369600) == $dm ) return true;
if ( date($format, $easter + 4320000) == $dm ) return true;
return false;
}
feel free to use / modify.
[#3] luca at musician dot org [2012-05-03 15:19:01]
Due to range limitations of core functions such as easter_date(), mktime(), strtotime(), I wrote this function to get the Easter Day in string format yyyy-mm-dd.
function myEaster($year)
{
//The next line would do the work if there were no limitations:
//return date("Y-m-d",easter_date($year));
$march21=date("$year-03-21");
$days=easter_days($year);
if($year<=2037)
//The next line would do the work if strtotime() wasn't affected by same limitations. But, the if..else is required to handle all years.
$date = date("Y-m-d",strtotime(date("Y-m-d", strtotime($march21)) . " +$days day"));
else
{
if($days<=10){
$day=str_pad(21+$days, 2, '0', STR_PAD_LEFT);
$date=date("$year-03-$day");
}
else
{
$day=str_pad($days-10, 2, '0', STR_PAD_LEFT);
$date=date("$year-04-$day");
}
}
return $date;
}
[#4] py dot lebecq at gmail dot com [2010-03-11 07:44:45]
I recently had to write a function that allows me to know if today is a holiday.
And in France, we have some holidays which depends on the easter date. Maybe this will be helpful to someone.
Just modify in the $holidays array the actual holidays dates of your country.
<?php
protected static function getHolidays($year = null)
{
if ($year === null)
{
$year = intval(date('Y'));
}
$easterDate = easter_date($year);
$easterDay = date('j', $easterDate);
$easterMonth = date('n', $easterDate);
$easterYear = date('Y', $easterDate);
$holidays = array(
// These days have a fixed date
mktime(0, 0, 0, 1, 1, $year), // 1er janvier
mktime(0, 0, 0, 5, 1, $year), // F??te du travail
mktime(0, 0, 0, 5, 8, $year), // Victoire des alli??s
mktime(0, 0, 0, 7, 14, $year), // F??te nationale
mktime(0, 0, 0, 8, 15, $year), // Assomption
mktime(0, 0, 0, 11, 1, $year), // Toussaint
mktime(0, 0, 0, 11, 11, $year), // Armistice
mktime(0, 0, 0, 12, 25, $year), // Noel
// These days have a date depending on easter
mktime(0, 0, 0, $easterMonth, $easterDay + 2, $easterYear),
mktime(0, 0, 0, $easterMonth, $easterDay + 40, $easterYear),
mktime(0, 0, 0, $easterMonth, $easterDay + 50, $easterYear),
);
sort($holidays);
return $holidays;
}
?>
[#5] peter dot burden at gmail dot com [2010-01-28 16:55:34]
In 5.3.1 easter_date() returns GMT of start of Easter Day in UK allowing
for UK Summer Time. If you are in another time zone you need to
calculate offsets.
<?php
$e1 = easter_date(2008);
$e2 = easter_date(2009);
echo "Timestamps " . $e1 . " " . $e2 . "\n";
// Timestamps 1206230400 1239490800
echo "Days between Easter 2008 Easter 2009 = " . ($e2-$e1)/86400 . "\n";
// Days between Easter 2008 Easter 2009 = 384.958333333 - i.e. 384 days 23 hours
date_default_timezone_set("Europe/London");
echo date( " l, jS F Y H:i TO",$e1) . "\n";
echo date( " l, jS F Y H:i TO",$e2) . "\n";
// Sunday, 23rd March 2008 00:00 GMT+0000
// Sunday, 12th April 2009 00:00 BST+0100
date_default_timezone_set("America/New_York");
echo date( " l, jS F Y H:i TO",$e1) . "\n";
echo date( " l, jS F Y H:i TO",$e2) . "\n";
// Saturday, 22nd March 2008 20:00 EDT-0400
// Saturday, 11th April 2009 19:00 EDT-0400
// Daylight saving time in effect - New York 4 hours behind GMT
?>
[#6] maxie [2008-06-12 01:36:46]
To compute the correct Easter date for Eastern Orthodox Churches I made a function based on the Meeus Julian algorithm:
<?php
function orthodox_eastern($year) {
$a = $year % 4;
$b = $year % 7;
$c = $year % 19;
$d = (19 * $c + 15) % 30;
$e = (2 * $a + 4 * $b - $d + 34) % 7;
$month = floor(($d + $e + 114) / 31);
$day = (($d + $e + 114) % 31) + 1;
$de = mktime(0, 0, 0, $month, $day + 13, $year);
return $de;
}
?>
[#7] nigelf at esp dot co dot uk [2008-01-28 03:50:23]
v5.2.1 - There is a known bug with easter_date() that can return incorrect dates for some years:
<?php
// 2008 OK
echo date("D d M Y", easter_date(2008)); // Sun 23 Mar 2008
// 2009 returns Saturday
echo date("D d M Y", easter_date(2009)); // Sat 11 Apr 2009
?>
However easter_days() works correctly:
<?php
echo date("D d M Y", strtotime("2009-03-21 +".easter_days(2009)." days")); // Sun 12 Apr 2009
?>
It is apparently related to timezone settings.
[#8] [2006-08-14 07:46:15]
I made the function like this ... works fine !
<?php
function ostern
{
$maerz21=date('z',mktime(0,0,0,3,21,$jb));
$d=((15 + $jb/100 - $jb/400 - (8 * $jb/100 + 13) / 25)%30 + 19 * ($jb%19))%30;
if ($d==29)
{
$D=28;
}
elseif($d==28 && ($jb%17)>=11)
{
$D=27;
}
else $D=$d;
$e=(2 * ($jb%4) + 4 *($jb%7) + 6 * $D + (6 + $jb/100 - $jb/400 - 2)%7)%7;
$ostersonntag=$e+$D+1+$maerz21;
return $ostersonntag;
}
?>
[#9] phpuser [2004-11-08 08:17:16]
The algorithm from Bigtree is correct if you add some (int) cast
<?php
function easter_date ($Year) {
$G = $Year % 19;
$C = (int)($Year / 100);
$H = (int)($C - (int)($C / 4) - (int)((8*$C+13) / 25) + 19*$G + 15) % 30;
$I = (int)$H - (int)($H / 28)*(1 - (int)($H / 28)*(int)(29 / ($H + 1))*((int)(21 - $G) / 11));
$J = ($Year + (int)($Year/4) + $I + 2 - $C + (int)($C/4)) % 7;
$L = $I - $J;
$m = 3 + (int)(($L + 40) / 44);
$d = $L + 28 - 31 * ((int)($m / 4));
$y = $Year;
$E = mktime(0,0,0, $m, $d, $y);
return $E;
}
?>