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gmstrftime — 根据区域设置格式化 GMT/UTC 时间/日期
$format
[, int $timestamp
] )和 strftime() 的行为相同,只除了返回时间是格林威治标准时(GMT)。例如,当在东部标准时(EST,GMT -500)运行时,下面第一行显示“Dec 31 1998 20:00:00”,而第二行显示“Jan 01 1999 01:00:00”。
Example #1 gmstrftime() 例子
<?php
setlocale ( LC_TIME , 'en_US' );
echo strftime ( "%b %d %Y %H:%M:%S" , mktime ( 20 , 0 , 0 , 12 , 31 , 98 )). "\n" ;
echo gmstrftime ( "%b %d %Y %H:%M:%S" , mktime ( 20 , 0 , 0 , 12 , 31 , 98 )). "\n" ;
?>
参见 strftime() 。
[#1] pvdster at hotmail dot com [2005-03-22 07:50:13]
If you want the dutch time on your pages and you are hosted on a server in the USA you can easily change it this way:
<?php
setlocale(LC_TIME, 'nl_NL');
$tgl = gmstrftime("%d %B %Y - %H:%M uur",time()+3600);
?>
Then use $tgl to display the right time.
Note the +3600 is a day light savings time correction.
The result: 22 maart 2005 - 16:39 uur
First I used the normal date function and this was the previous result: March 22, 2005 - 04:28 AM
I needed it for a dutch guestbook.
I'm new to PHP and it took me a while to find it out and maybe it's of no use for experienced PHP programmers but I thought people can always ignore my post :)
[#2] peter dot albertsson at spray dot se [2005-02-05 07:27:17]
gmstrftime() should not be used to generate a RFC 850 date for use in HTTP headers, since its output is affected by setlocale().
Use gmdate instead:
gmdate('D, d M Y H:i:s') . ' GMT';
[#3] yellow dot snow at huskies dot com [2004-10-10 09:15:34]
HTTP 1.1 (RFC 2068) requires an RFC 1123 date with a four digit year, so the correct format to use for a Last-modified header would look something like this:
<?php
header("Last-modified: " .
gmstrftime("%a, %d %b %Y %T %Z",getlastmod()));
?>
[#4] neo at gothic-chat d0t de [2004-06-24 23:27:15]
To get a RFC 850 date (used in HTTP) of the current time:
gmstrftime ("%A %d-%b-%y %T %Z", time ());
This will get for example:
Friday 25-Jun-04 03:30:23 GMT
Please note that times in HTTP-headers _must_ be GMT, so use gmstrftime() instead of strftime().