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(PHP 5 >= 5.0.0)
ArrayObject::offsetGet — Returns the value at the specified index
$index
)
index
The index with the value.
The value at the specified index or NULL
.
Produces an E_NOTICE
error message when the specified
index does not exist.
Example #1 ArrayObject::offsetGet() example
<?php
$arrayobj = new ArrayObject (array( 'zero' , 7 , 'example' => 'e.g.' ));
var_dump ( $arrayobj -> offsetGet ( 1 ));
var_dump ( $arrayobj -> offsetGet ( 'example' ));
var_dump ( $arrayobj -> offsetExists ( 'notfound' ));
?>
以上例程会输出:
int(7) string(4) "e.g." bool(false)
[#1] Alex Andrienko [2009-01-20 03:58:16]
Speaking of offsetGet() method overloading, be advised, that if you're iterating through Object via foreach, this method wouldn't be called. Iterator's current() method will be called instead.
[#2] Sam [2007-11-30 03:01:55]
If you're overloading ArrayObject, it's worth noting that while this method (when implemented by the parent) will return a reference, so code like $fakeArray['foobar']['hello'] = 1; will work like you expect.
However, when you overload the offsetGet method, you CANNOT define it as &offsetGet, so the above code falls out (because it returns the 'foobar' variable before you actually work with it).
This is something that the developers broke between 5.0 and 5.1, and was closed as bogus (http://bugs.php.net/bug.php?id=34783). So this is not a big, or question, or request, but just something worth noting.