在测试生产消费者模型的时候遇到这样一个问题,在继承线程后 加了个标志位 mark
class Consumer(threading.Thread):
def __init__(self, queue):
threading.Thread.__init__(self)
self._queue = queue
self.mark = True
def run(self):
while self.mark:
msg = self._queue.get()
if isinstance(msg, str) and msg == 'quit':
break
print("I'm a thread, and I received %s!!" % msg)
print('Bye byes!')
def producer():
q = queue.Queue()
worker = Consumer(q)
worker.start() # 开启消费者线程
start_time = time.time()
while time.time() - start_time < 5:
q.put('something at %s' % time.time())
time.sleep(1)
worker.mark = Flese
worker.join()
我原先指望 通过这个标志位来实现线程的结束控制,但实际效果是程序卡死在worker.join()
完全没有退出。
请教下,这是什么原因?
雷雷