<?php echo '<div class="content_banner3">'; 回显'<ul>'； foreach($user as $key=>$value){ echo '<li>'; 欧共体

新手问下，a标签怎么去传值给其他页面-PHP中文网问答

<?php

echo '

foreach($user as $key=>$value){

# echo '

';
echo '
';
echo "
echo '
';
echo '
';
echo ' '.$value['name'].'';
echo ''.$value['pice'].'';
$user = array(0=>"缺货", 1=>"有货");
$uu = $value["库存" ];
echo ''.$user[$uu].'';
echo ''.$value['content'].'';
$a = $value['id'];
echo "";
echo '< ;/div>';
echo '

}

echo '

？ >

我想echo "<a class='introduce_3' href='shop_list.php?id=$value[$a]' >购买</a>"; 获取出id传到但是shop_list.php这个页面收到他的id，现在报错，Notice: Undefined offset: 1 ，Notice: Undefined offset: 2这些，值也没有传成功，具体写法是啥呢