获取第二个重复列的SQL查询结果。
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P粉037880905 2023-08-02 12:42:13
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<p>我在运行SQL查询时遇到了一个挑战:<br /><br />有两个表:</p><p><br /></p> <ul> <li>Sample Table 01</li> </ul> <table class="s-table"> <thead> <tr> <th>Ext. Initial ID</th> <th>Description</th> </tr> </thead> <tbody> <tr> <td>1111</td> <td>start11</td> </tr> <tr> <td>1112</td> <td>start12</td> </tr> <tr> <td>1113</td> <td>start13</td> </tr> <tr> <td>1114</td> <td>start14</td> </tr> <tr> <td>1115</td> <td>start15</td> </tr> <tr> <td>1116</td> <td>start16</td> </tr> <tr> <td>1117</td> <td>start17</td> </tr> <tr> <td>1118</td> <td>start18</td> </tr> <tr> <td>1119</td> <td>start19</td> </tr> <tr> <td>1120</td> <td>start20</td> </tr> </tbody> </table> <ul> <li>Sample Table 02</li> </ul> <table class="s-table"> <thead> <tr> <th>Ext. Initial ID</th> <th>Ext. Level one ID</th> </tr> </thead> <tbody> <tr> <td>1111</td> <td>1115</td> </tr> <tr> <td>1112</td> <td>1115</td> </tr> <tr> <td>1113</td> <td>1113</td> </tr> <tr> <td>1114</td> <td>1113</td> </tr> <tr> <td>1115</td> <td>1113</td> </tr> <tr> <td>1116</td> <td>1113</td> </tr> <tr> <td>1117</td> <td>1119</td> </tr> <tr> <td>1118</td> <td>1119</td> </tr> <tr> <td>1119</td> <td>1119</td> </tr> <tr> <td>1120</td> <td>1119</td> </tr> </tbody> </table> <p>"Ext. Initial ID"和"Description"列是唯一的。<br /><br />而"Ext. Level one ID"是重复的(但它基本上是"Ext. Initial ID"的一部分)。</p><p><br /></p> <pre class="brush:php;toolbar:false;">**Query Im using:** SELECT I.external_initial_id, C.external_level_one_id, I.description FROM sample_table_01 AS I inner join sample_table_02 AS C ON I.external_initial_id = C.external_initial_id</pre> <p>现在,我只需要一些"Ext. Initial ID"的结果,所以我使用一个过滤器(以逗号分隔的方式在仪表板中)将它们放入查询中,查询结果如下:</p> <pre class="brush:php;toolbar:false;"> | Ext. Initial ID | Ext. Level one ID | Description | | -------- | -------- | -------- | | 1111 | 1115 | start11 | | 1112 | 1115 | start12 | | 1113 | 1113 | start13 | | 1114 | 1113 | start14 | | 1117 | 1119 | start17 | | 1119 | 1119 | start19 |</pre> <p>在这里,我得到了与表01中的"Ext. Initial ID"相关联的"description"列。<br /><br />然而,我想要的是与"Ext. Level one ID"相关联的"description"列(即来自另一个表的结果列)。<br /><br />我期望的输出是:</p><p><br /></p> <table class="s-table"> <thead> <tr> <th>Ext. Initial ID</th> <th>Ext. Level one ID</th> <th>Description</th> </tr> </thead> <tbody> <tr> <td>1111</td> <td>1115</td> <td>start15</td> </tr> <tr> <td>1112</td> <td>1115</td> <td>start15</td> </tr> <tr> <td>1113</td> <td>1113</td> <td>start13</td> </tr> <tr> <td>1114</td> <td>1113</td> <td>start13</td> </tr> <tr> <td>1117</td> <td>1119</td> <td>start19</td> </tr> <tr> <td>1119</td> <td>1119</td> <td>start19</td> </tr> </tbody> </table><p><br /></p>
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P粉138871485

你可以尝试使用以下的查询语句:

SELECT C.external_initial_id,C.external_level_one_id,I.description FROM sample_table_02 AS C inner join sample_table_01 AS I ON C.external_level_one_id = I.external_initial_id

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