基于起始时间和结束时间的数据进行小时计数
P粉283559033
P粉283559033 2023-08-30 15:53:41
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<p>在表格中,数据以时间戳格式存在,但我以时间(start_at)和时间(end_at)的格式共享它。</p> <p>表格结构:</p> <pre class="brush:php;toolbar:false;">id, start_at, end_at 1, 03:00:00, 06:00:00 2, 02:00:00, 05:00:00 3, 01:00:00, 08:00:00 4, 08:00:00, 13:00:00 5, 09:00:00, 21:00:00 6, 13:00:00, 16:00:00 6, 15:00:00, 19:00:00</pre> <p>对于结果,我们需要计算在start_at和end_at时间之间活动的id数量。</p> <pre class="brush:php;toolbar:false;">hours, count 0, 0 1, 1 2, 2 3, 3 4, 3 5, 2 6, 1 7, 1 8, 1 9, 2 10, 2 11, 2 12, 2 13, 3 14, 2 15, 3 16, 2 17, 2 18, 2 19, 1 20, 1 21, 0 22, 0 23, 0</pre></p>
P粉283559033
P粉283559033

全部回复(1)
P粉432930081

要么

WITH RECURSIVE
cte AS (
    SELECT 0 `hour`
    UNION ALL
    SELECT `hour` + 1 FROM cte WHERE `hour` < 23
)
SELECT cte.`hour`, COUNT(test.id) `count`
FROM cte 
LEFT JOIN test ON cte.`hour` >= HOUR(test.start_at)
              AND cte.`hour` < HOUR(test.end_at)
GROUP BY 1
ORDER BY 1;

要么

WITH RECURSIVE
cte AS (
    SELECT CAST('00:00:00' AS TIME) `hour`
    UNION ALL
    SELECT `hour` + INTERVAL 1 HOUR FROM cte WHERE `hour` < '23:00:00'
)
SELECT cte.`hour`, COUNT(test.id) `count`
FROM cte 
LEFT JOIN test ON cte.`hour` >= test.start_at 
              AND cte.`hour` < test.end_at 
GROUP BY 1
ORDER BY 1;

第一个查询以时间格式返回小时列,而第二个查询以数值形式返回此列。选择对您来说安全的变体。

https://dbfiddle.uk/?rdbms=mysql_8.0&fiddle=5a77b6e3158be06c7a551cb7e64673de

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