如何将函数从闭包转移到普通函数

Question

我正在尝试使害虫测试文件更易于阅读。

目前，我有一些标准测试：

test('can get subscribers latest subscription', function () {
     $this->seed(PlansTestSeeder::class);
    $this->seed(SubscriptionsTestSeeder::class);

    $this->assertDatabaseCount('plans', 2);
    $this->assertDatabaseCount('subscriptions', 0);


    Subscription::factory()->create([
        "plan_id" => Plan::where("slug", "bronze")->first()->id
    ]);
    Subscription::factory()->create([
        "plan_id" => Plan::where("slug", "silver")->first()->id
    ]);
    Subscription::factory()->create([
        "plan_id" => Plan::where("slug", "silver")->first()->id,
        "status"  => "expired"
    ]);
    Subscription::factory()->trashed()->create();

    $this->assertDatabaseCount('subscriptions', 4);

});

test('can get subscribers active subscriptions', function () {
    $this->seed(PlansTestSeeder::class);
    $this->seed(SubscriptionsTestSeeder::class);

    $silverPlan = Plan::where("slug", "silver")->first();

    $subscription1 = Subscription::factory()->create([
        "plan_id"         => Plan::where("slug", "silver")->first()->id,
        "subscriber_id"   => 1,
        "subscriber_type" => "ApresourcingFramework\Billing\Tests\Models\Subscriber",
        "created_at"      => now()->subDays(2),
        "started_at"      => now()->subDays(2)
    ]);
    $subscription2 = Subscription::factory()->create([
        "plan_id"         => $silverPlan->id,
        "subscriber_id"   => 1,
        "subscriber_type" => "ApresourcingFramework\Billing\Tests\Models\Subscriber",
        "created_at"      => now()->subDays(1),
        "started_at"      => now()->subDays(1)
    ]);

    $user         = Subscriber::find(1);
    $subscription = $user->latestSubscription();
    expect($subscription->id)->toBe($subscription2->id);
});

但是为了提醒自己我编写了哪些测试，我必须一遍又一遍地上下滚动页面。

我想做的是更改为如下内容：

test('can get subscribers latest subscription', getLatestSubscription());
test('can get subscribers active subscriptions', getActiveSubscriptions());

function getLatestSubscription() {
    /// function code here
});

function getActiveSubscriptions() {
    // function code here
});

但是，测试函数包含对 $this 的引用，它在正常闭包中可用，但在标准函数中不可用，因为我在此处设置了它。

编辑：我正在使用 laravel pest 插件 - 我不确定这是否会对 $this 的使用产生影响

有什么办法可以解决这个问题吗？

Answer 1

感谢回复中的一些提示。不像我希望的那样整洁，但至少这意味着所有测试（“测试描述”）调用都位于 php 文件底部的一个位置。

$createSubscription = function () {

    $this->seed(PlansTestSeeder::class);
    $this->seed(SubscriptionsTestSeeder::class);

    $this->assertDatabaseCount('plans', 2);
    $this->assertDatabaseCount('subscriptions', 0);


    Subscription::factory()->create([
        "plan_id" => Plan::where("slug", "bronze")->first()->id
    ]);
    Subscription::factory()->create([
        "plan_id" => Plan::where("slug", "silver")->first()->id
    ]);
    Subscription::factory()->create([
        "plan_id" => Plan::where("slug", "silver")->first()->id,
        "status"  => "expired"
    ]);
    Subscription::factory()->trashed()->create();

    $this->assertDatabaseCount('subscriptions', 4);

};

$createBronzeSubscription = function () {
    $this->seed(PlansTestSeeder::class);
    $this->seed(SubscriptionsTestSeeder::class);

    Subscription::factory()->create([
        "plan_id" => Plan::where("slug", "bronze")->first()->id
    ]);

    $this->assertDatabaseCount('subscriptions', 1);
};


test('can create subscription', function () use ($createSubscription) {
    return \Closure::bind(\Closure::fromCallable($createSubscription), $this, get_class($this))($this);
});

test('can create bronze subscription', function () use ($createBronzeSubscription) {
    return \Closure::bind(\Closure::fromCallable($createBronzeSubscription), $this, get_class($this))($this);
});