在MySQL中使用2个表进行计算

Question

我有 2 张桌子 游戏和交易 我在 Games 表中使用此公式 sum(EntryFee * Rake/(100 Rake)*TotalEntry) 来获取值

我在事务表计数（不同的用户ID）中使用此查询来获取值

现在我想将 [sum(EntryFee * Rake/(100 Rake)*TotalEntry)] 的值除以 [count(distinct UserID)] 的值

例如 sum(EntryFee * Rake/(100 Rake)*TotalEntry) = 90 且 count(distinct UserID) = 3 那么 90/3 =30 我怎样才能在 MYSQL 中做到这一点

Answer 1

CREATE TABLE Games (EntryFee INT, Rake INT, TotalEntry INT);
CREATE TABLE Transaction1 (UserID VARCHAR(25));

INSERT INTO Games VALUES 
    (30,16,150),(45,20,100),(15,5,50),(25,20,300),(10,8,270);

INSERT INTO Transaction1 VALUES ('Daniel'),('David'),('John'),('Martha');

SELECT Games.EntryFee, Games.Rake, Games.TotalEntry, COUNT(distinct Transaction1.UserID) AS CountUser,
(Games.EntryFee * Games.Rake / (100 + Games.Rake) * Games.TotalEntry / COUNT(distinct Transaction1.UserID))
AS Calculate
FROM Games JOIN Transaction1 GROUP BY Games.EntryFee, Games.Rake, Games.TotalEntry;

结果：

+==========+======+============+===========+==============+
| EntryFee | Rake | TotalEntry | CountUser | Calculate    |
+==========+======+============+===========+==============+
| 10       | 8    | 270        | 4         | 50.00000000  |
+----------+------+------------+-----------+--------------+
| 15       | 5    | 50         | 4         | 8.92857500   |
+----------+------+------------+-----------+--------------+
| 25       | 20   | 300        | 4         | 312.50000000 |
+----------+------+------------+-----------+--------------+
| 30       | 16   | 150        | 4         | 155.17242500 |
+----------+------+------------+-----------+--------------+
| 45       | 20   | 100        | 4         | 187.50000000 |
+----------+------+------------+-----------+--------------+

示例查询

Answer 2

雷雷