Python如何让倒计时效果的在固定区域刷新

Answer 1

不好意思，又是我。
再科普一个 "b" 是退格的意思，它会向左移动一格并删除该格子上现实的字符，详情请参考ascii编码表

办法无非就两个

1) 整行覆盖。

pythonimport sys, time

def interface_show(**kwargs):
    lineTmpla = ' '*5 + kwargs['title'] + kwargs['artist'] + kwargs['rate'] + " %-3s"
    print time_remain(lineTmpla, kwargs['minutes']),

def time_remain(lineTmpla, mins):
    count = 0 
    while (count < mins):
        count += 1
        n = mins - count
        time.sleep(1)
        sys.stdout.write("\r" + lineTmpla %(n),)
        sys.stdout.flush()
        if not n:
            return 'completed'

interface_show(title="倒计时demo", artist="哗嚓啊", rate="揍起来", minutes=5)

2) 局部覆盖

需要移动光标，在下暂时只知道 b，有人知道其它并愿意告知的话就太感谢了

pythonimport sys, time

def interface_show(**kwargs):
    print ' '*5, kwargs['title'], kwargs['artist'], kwargs['rate'], time_remain(kwargs['minutes'])

def time_remain(mins):
    count = 0
    length = len(str(mins))
    sys.stdout.write(" " * length,)
    while (count < mins):
        count += 1
        n = mins - count
        time.sleep(1)
        sys.stdout.write(('\b' * length) + str(n),)
        sys.stdout.flush()
        if not n:
            return 'completed'

interface_show(title="倒计时demo", artist="哗嚓啊", rate="揍起来", minutes=5)