python 中列表怎么分区间统计

Question

list= [
    ...,
    2648, 2648, 2648, 63370, 63370, 425, 425, 120,
    120, 217, 217, 189, 189, 128, 128, 115, 115, 197,
    19752, 152, 152, 275, 275, 1716, 1716, 131, 131,
    98, 98, 138, 138, 277, 277, 849, 302, 152, 1571,
    68, 68, 102, 102, 92, 92, 146, 146, 155, 155,
    9181, 9181, 474, 449, 98, 98, 59, 59, 295, 101,
    ...
]

for i in list:
    if int(i/50)+1 not in dic:
        dic(int(i /50)+1)=list.count(i)
    else:
        dic(int(i /50)+1)+=list.count(i)

我这么写总是报错，我想以 50bp 为一个区间进行统计，即统计长度在 0-50 的频数，50-100 的频数...

我这么写对么，应该怎么写呢?

Answer 1

# code for python3
from itertools import groupby

lst= [
    2648, 2648, 2648, 63370, 63370, 425, 425, 120,
    120, 217, 217, 189, 189, 128, 128, 115, 115, 197,
    19752, 152, 152, 275, 275, 1716, 1716, 131, 131,
    98, 98, 138, 138, 277, 277, 849, 302, 152, 1571,
    68, 68, 102, 102, 92, 92, 146, 146, 155, 155,
    9181, 9181, 474, 449, 98, 98, 59, 59, 295, 101, 5
]

for k, g in groupby(sorted(lst), key=lambda x: x//50):
    print('{}-{}: {}'.format(k*50, (k+1)*50-1, len(list(g))))

结果:

0-49: 1
50-99: 10
100-149: 15
150-199: 8
200-249: 2
250-299: 5
300-349: 1
400-449: 3
450-499: 1
800-849: 1
1550-1599: 1
1700-1749: 2
2600-2649: 3
9150-9199: 2
19750-19799: 1
63350-63399: 2

---

1. 不要使用内建函数的名字: list 作为变数名

2. 你想要的区间重叠了, 比如说元素 50 就不知道要分在 0-50 还是 50-100 了

3. 存取字典应该用 [] 而不是 ()

---

我回答过的问题: Python-QA

Answer 2

for i in list i是list中的内容，应该是for I in range(len(list))