


PHP calender (calendar) two version code examples (solve the 2038 problem)_PHP tutorial
Note that 32-bit machines have a 2038 problem, so the age range of 32-bit servers is 1970~2038
We can also use DateTime to avoid this problem (this has nothing to do with 32-bit and 64-bit)
/**
*
* 我的日历
* date_default_timezone_set date mktime
* @param int $year
* @param int $month
* @param string $timezone
* @author fc_lamp
* @blog: fc-lamp.blog.163.com
*/
function myCalender($year = '', $month = '', $timezone = 'Asia/Shanghai')
{
date_default_timezone_set ( $timezone );
$year = abs ( intval ( $year ) );
$month = abs ( intval ( $month ) );
//是否是32位机
if (is32())
{
if ($year < 1970 or $year >= 2038)
{
$year = date ( 'Y' );
}
} else
{
if ($year <= 0)
{
$year = date ( 'Y' );
}
}
if ($month <= 0 or $month > 12)
{
$month = date ( 'm' );
}
//上一年
$pretYear = $year - 1;
//上一月
$mpYear = $year;
$preMonth = $month - 1;
if ($preMonth <= 0)
{
$preMonth = 1;
$mpYear = $pretYear;
}
//下一年
$nextYear = $year + 1;
//下一月
$mnYear = $year;
$nextMonth = $month + 1;
if ($nextMonth > 12)
{
$nextMonth = 1;
$mnYear = $nextYear;
}
//日历头
$html = <<
上一年 | 上一月 | 回到今天 | 下一月 | 下一年 | ||||||||||
{$year}年{$month}月 | ||||||||||||||
HTML; $currentDay = date ( 'Y-m-j' ); //当月最后一天 $lastday = date ( 'j', mktime ( 0, 0, 0, $nextMonth, 0, $year ) ); //循环输出天数 $day = 1; $line = ''; while ( $day <= $lastday ) { $cday = $year . '-' . $month . '-' . $day; //当前星期几 $nowWeek = date ( 'N', mktime ( 0, 0, 0, $month, $day, $year ) ); if ($day == 1) { $line = ''; $line .= str_repeat ( '', $nowWeek - 1 ); } if ($cday == $currentDay) { $style = 'style="color:red;"'; } else { $style = ''; } $line .= ""; //一周结束 if ($nowWeek == 7) { $line .= ''; $html .= $line; $line = ''; } //End of the month if ($day == $lastday) { if ($nowWeek != 7) { $line .= str_repeat ( '', 7 - $nowWeek ); } $line .= ''; $html .= $line; break; } $day ++; } $html .= <<
|
HTML;
return $html;
}
/**
*
* Check if it is a 32-bit machine
* @author fc_lamp
* @blog: fc-lamp.blog.163.com
*/
function is32()
{
$is32 = False;
if (strtotime ( '2039-10-10' ) === False)
{
$is32 = True;
}
return $is32;
}
Use the DateTime class to solve the 2038 problem, so that there is no distinction between 32-bit and 64-bit. The code is as follows:
/**
*
* My calendar (DateTime version)
* date_default_timezone_set date mktime
* @param int $year
* @param int $month
* @param string $timezone
* @author fc_lamp
* @blog: fc-lamp.blog.163.com
*/
function myCalender($year = '', $month = '', $timezone = 'Asia/Shanghai')
{
date_default_timezone_set ( $timezone );
$year = abs ( intval ( $year ) );
$month = abs ( intval ( $month ) );
$nowDate = new DateTime();
if ($year <= 0)
{
$year = $nowDate->format( 'Y' );
}
if ($month <= 0 or $month > 12)
{
$month = $nowDate->format('m' );
}
//上一年
$pretYear = $year - 1;
//上一月
$mpYear = $year;
$preMonth = $month - 1;
if ($preMonth <= 0)
{
$preMonth = 1;
$mpYear = $pretYear;
}
//下一年
$nextYear = $year + 1;
//下一月
$mnYear = $year;
$nextMonth = $month + 1;
if ($nextMonth > 12)
{
$nextMonth = 1;
$mnYear = $nextYear;
}
//日历头
$html = <<
上一年 | 上一月 | 回到今天 | 下一月 | 下一年 | ||||||||||
{$year}年{$month}月 | ||||||||||||||
HTML; $currentDay = $nowDate->format('Y-m-j' ); //当月最后一天 $creatDate = new DateTime("$year-$nextMonth-0"); $lastday = $creatDate->format('j'); $creatDate = NULL; //循环输出天数 $day = 1; $line = ''; while ( $day <= $lastday ) { $cday = $year . '-' . $month . '-' . $day; //当前星期几 $creatDate = new DateTime("$year-$month-$day"); $nowWeek = $creatDate->format('N'); $creatDate = NULL; if ($day == 1) { $line = ''; $line .= str_repeat ( '', $nowWeek - 1 ); } if ($cday == $currentDay) { $style = 'style="color:red;"'; } else { $style = ''; } $line .= ""; //一周结束 if ($nowWeek == 7) { $line .= ''; $html .= $line; $line = ''; } //End of the month if ($day == $lastday) { if ($nowWeek != 7) { $line .= str_repeat ( '', 7 - $nowWeek ); } $line .= ''; $html .= $line; break; } $day ++; } $html .= <<
|
HTML;
return $html;
}

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